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Full Discussion: Not replacing using sed
Top Forums Shell Programming and Scripting Not replacing using sed Post 302943266 by clx on Thursday 7th of May 2015 02:07:11 AM
Old 05-07-2015
Quote:
Originally Posted by ramkumar15
Hi all,

I am trying to change the below word. but the changes is not reflecting in the new file

Code:
 
sed -n 's/apple/orange/'  filename

You have used -n switch which is stopping output to be displayed on the screen.

Code:
sed 's/apple/orange/'  filename > newfile

If your version supports -i option then you can save the changes in the same file.

Code:
sed -i 's/apple/orange/'  filename

 

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ARSORT(3)								 1								 ARSORT(3)

arsort - Sort an array in reverse order and maintain index association

SYNOPSIS
bool arsort (array &$array, [int $sort_flags = SORT_REGULAR]) DESCRIPTION
This function sorts an array such that array indices maintain their correlation with the array elements they are associated with. This is used mainly when sorting associative arrays where the actual element order is significant. PARAMETERS
o $array - The input array. o $sort_flags - You may modify the behavior of the sort using the optional parameter $sort_flags, for details see sort(3). RETURN VALUES
Returns TRUE on success or FALSE on failure. EXAMPLES
Example #1 arsort(3) example <?php $fruits = array("d" => "lemon", "a" => "orange", "b" => "banana", "c" => "apple"); arsort($fruits); foreach ($fruits as $key => $val) { echo "$key = $val "; } ?> The above example will output: a = orange d = lemon b = banana c = apple The fruits have been sorted in reverse alphabetical order, and the index associated with each element has been maintained. SEE ALSO
asort(3), The comparison of array sorting functions. PHP Documentation Group ARSORT(3)
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