Another newbie to Unix scripting Q..
How do you assign a value resulting from a command, such as awk, to a variable.
I am currently trying:-
$awk '{print $1}' file1 > variable1
with no change to $variable1.
The line:
$awk '{print $1}' file1
does print the first line of the... (3 Replies)
Hi
In my shell script, I'm trying to find the line count of a file and assign it to a variable.
LINE_COUNT=$(wc -l $FILE_NAME)
But when i display LINE_COUNT, i'm getting the linecount concatenated with the file name. I want only the number. How can i get the line count alone ? Someone... (2 Replies)
hi all,
in ksh, how do i assign the output of a find command to a variable, e.g
am trying something like this :
totalNoFiles=$(print find ./ -name "SystemOut*.log");
but when i echo $totalNoFiles it displays
find ./ -name "SystemOut*.log"
instead of the total number of... (2 Replies)
can we make a global variable and store character values and add other values to that variable ?? for example
a="hello, John"
and can we add value ". How are you? so
a can have
"hello, John. How are you?"
can someone help me?? (2 Replies)
Hi folks.
I have this variable called FirstIN that contains something like this: 001,002,003,004...
I am trying to assign the content of this variable into ModifiedIN but with the following format : 001 002 003 004...(changing the commas for spaces)
I thought about using sed but i am not... (17 Replies)
my script is some thing like this
i11="{1,2,3,4,5,6,7,8,9,10,11,}"
echo "enter value"
read value ..............suppose i11
x="$value"
echo "$($value)" .............the echo should be {1,2,3,4,5,6,7,8,9,10,11,}
but its showing "i11" only.
plz help me out to get desired... (10 Replies)
Hi,
I have a list of files in a directory. Each file has a .txt and a .log extension i.e. file.txt & file.log, file1.txt & file1.log etc. The file with the .log extension may not always exist alongside the file with the .txt extension.
I need to copy the .txt file if there is a corresponding... (6 Replies)
Hi
I have a script that accepts an input date in YYYY-MM-DD format.
After that, I used sed to delete the hyphen (-) which gives me an output YYYY MM DD.
My question is, how can I assign those three numbers to a three different variable.
Example:
2013-11-23 will become 2013 11 23... (4 Replies)
Unable to get the value to a variable.
set -x
cd $HOME
echo "Enter the server name"
read a
echo $a
i=4
j=1
k = ps -ef | awk '/server1/{ print $4 }' | tail -$i | head -$j`
echo $k
When I do the same in command line it works, however the same does not work when I provide that in the... (1 Reply)
Discussion started by: venkidhadha
1 Replies
LEARN ABOUT CENTOS
drop_extension
DROP EXTENSION(7) PostgreSQL 9.2.7 Documentation DROP EXTENSION(7)NAME
DROP_EXTENSION - remove an extension
SYNOPSIS
DROP EXTENSION [ IF EXISTS ] name [, ...] [ CASCADE | RESTRICT ]
DESCRIPTION
DROP EXTENSION removes extensions from the database. Dropping an extension causes its component objects to be dropped as well.
You must own the extension to use DROP EXTENSION.
PARAMETERS
IF EXISTS
Do not throw an error if the extension does not exist. A notice is issued in this case.
name
The name of an installed extension.
CASCADE
Automatically drop objects that depend on the extension.
RESTRICT
Refuse to drop the extension if any objects depend on it (other than its own member objects and other extensions listed in the same
DROP command). This is the default.
EXAMPLES
To remove the extension hstore from the current database:
DROP EXTENSION hstore;
This command will fail if any of hstore's objects are in use in the database, for example if any tables have columns of the hstore type.
Add the CASCADE option to forcibly remove those dependent objects as well.
COMPATIBILITY
DROP EXTENSION is a PostgreSQL extension.
SEE ALSO
CREATE EXTENSION (CREATE_EXTENSION(7)), ALTER EXTENSION (ALTER_EXTENSION(7))
PostgreSQL 9.2.7 2014-02-17 DROP EXTENSION(7)