Need Help to delete carriage return and new line in csv file Post: 302942972

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Hello, I have a file that has got carriage returns in it and I want to take them out. Anyone know how I can do this in a ksh? thanks

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Hello I'm trying to write a shell script which can remove a carriage return and/or line feed from a file, so the resulting file all ends up on one line. So, I begin with a file like this text in file!<CR> line two!<CR> line three!<CR> END!<CR> And I want to end up with a file...

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Could someone tell me how to do the below without opening the file? (eg in sed or awk) I have a file with the contenst below: $ more file1.txt 10 AAA; 200 BBB; 3 CCC; I want to delete the carriage return of one line above the line which has ";" at the end to get the...

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Delete carriage return in SED

Hi everybody! I'm working in one script with sed, I have file with the next content: <voms.db.type value="changeme"/> <voms.db.host value="changeme"/> <voms.admin.smtp.host value="changeme"/> <voms.mysql.admin.password value="changeme"/> <glite.installer.verbose value="true"/> ...

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Hi All, I am reading two files and writing out the file name and count of lines in each file to an output file. My script looks like this: echo "input_file1.out;`wc -l < input_file1.out | sed 's/^]*$.*$]*$/\1/'` " > comp_file1.out echo "input_file2.out;`wc -l < input_file2.out | sed...

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Hi I am using sed command to make SCORE=somevalue to SCORE=blank in a file. Please see the attached lastline.txt file. After executing the below command on the file, it removes the last line. cat lastline.txt | sed 's/SCORE=.*$/SCORE=/g' > newfile.txt Why does sed command remove the...

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line carriage return characters

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LEARN ABOUT DEBIAN

shtool-path

SHTOOL-PATH.TMP(1)					      GNU Portable Shell Tool						SHTOOL-PATH.TMP(1)

NAME

       shtool-path - GNU shtool command dealing with shell path variables

SYNOPSIS

       shtool path [-s|--suppress] [-r|--reverse] [-d|--dirname] [-b|--basename] [-m|--magic] [-p|--path path] str [str ...]

DESCRIPTION

       This command deals with shell $PATH variables. It can find a program through one or more filenames given by one or more str arguments.  It
       prints the absolute filesystem path to the program displayed on "stdout" plus an exit code of 0 if it was really found.

OPTIONS

       The following command line options are available.

       -s, --suppress
	   Supress output. Useful to only test whether a program exists with the help of the return code.

       -r, --reverse
	   Transform a forward path to a subdirectory into a reverse path.

       -d, --dirname
	   Output the directory name of str.

       -b, --basename
	   Output the base name of str.

       -m, --magic
	   Enable advanced magic search for ""perl"" and ""cpp"".

       -p, --path path
	   Search in path. Default is to search in $PATH.

EXAMPLE

	#   shell script
	awk=`shtool path -p "${PATH}:." gawk nawk awk`
	perl=`shtool path -m perl`
	cpp=`shtool path -m cpp`
	revpath=`shtool path -r path/to/subdir`

HISTORY

       The GNU shtool path command was originally written by Ralf S.  Engelschall <rse@engelschall.com> in 1998 for Apache. It was later taken
       over into GNU shtool.

SEE ALSO

       shtool(1), which(1).

18-Jul-2008							   shtool 2.0.8 						SHTOOL-PATH.TMP(1)

10 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

carriage return/line feeds

Discussion started by: pitstop

2. Shell Programming and Scripting

Removing Carriage Return and or line feed from a file

Discussion started by: tbone231

3. Shell Programming and Scripting

How to insert carriage return before line feed?

Discussion started by: huey ing

4. Shell Programming and Scripting

How to delete carriage return in SED

Discussion started by: stevefox