Could I throw in a totally different suggestion? If you have a WANTED file with the required names and all the files should be in a single directory, could you follow this logic?:-
List all files in the directory
Use your WANTED file with grep to generate a list of all files that do exist.
Use grep again to check those still missing.
Something like this perhaps:-
It might mean fewer reads of the directory, although it does generate an intermediate file, so maybe, maybe not. There also might be confusion if your files are too similarly named, e.g. FileA arrives, but FileA1 is still missing, and this might not be spotted. You might need to mark the beginning and end of each line in the WANTED file with ^ & $ respectively.
Hi,
I am trying to find the content of file using grep and find command and list only the file names
but i am getting entire file list of files in the directory
find . -exec grep "test" {} \; -ls
Can anyone of you correct this (2 Replies)
Hi All ,
I am having confusion in a shell script. Please guide me.
I need to get multiple files (number of files vary time to time, file names are separated by '|') using FTP get from the remote server.
Actually, i call the FTP function in a loop. At the last step, i need to move all the get... (3 Replies)
I have to rename a large number of files so that the name of each file corresponds to a code number that is given side by side in a list (textfile).
The list contains in column A the filename of the actual files to be renamed and in column B the name (a client code, 9 digits) that has to be... (7 Replies)
Hi to all here ,
Excuse me for the lamer question but I need UNIX command for copying List of Files Under Different File Names !
for example I have this list:
new_001.jpg
new_002.jpg
new_003.jpg
.....
I want to copy all files that start with "new_" to the same directory but under... (7 Replies)
Hi,
I have a list of zipped files. I want to grep for a string in all files and get a list of file names that contain the string. But without unzipping them before that, more like using something like gzcat.
My OS is:
SunOS test 5.10 Generic_142900-13 sun4u sparc SUNW,SPARC-Enterprise (8 Replies)
OS : RHEL 6.1
Shell : Bash
I have lots of files in /tmp/stage directory as show below.
Using a loop, I need to print all the filenames in this directory except those ending with a number. How can I do this ?
# pwd
/tmp/stage
#
#
# ls -l *
-rw-r--r--. 1 root root 0 Oct 7 18:38 stmt1... (2 Replies)
Below is my script code.which shows the environment name and then fetch the file from the ftp server but I am facing one issue.The script should be run in both way.We can pass the arguments with script and select the environment name then file name.Here the issue is I am not able to list the files... (1 Reply)
Data files coming in different names in a file name called process.txt.
1. shipments_yyyymmdd.gz
2 Order_yyyymmdd.gz
3. Invoice_yyyymmdd.gz
4. globalorder_yyyymmdd.gz
The process needs to discard all the below files and only process two of the 4 file names available
... (1 Reply)
I'm interested in writing a report script using BASH that searches all of the files in a particular directory for a keyword and printing a list of files containing this string...
In fact this reporting script would have searches for multiple keywords, so I'm interested in making multiple... (2 Replies)
Hi ,
I'm trying to list the files and output is written to a file. But when I execute the command , the output file is being listed. How to exclude it ?
/tmp
file1.txt
file2.txt
ls -ltr |grep -v '-' | awk print {$9, $5} > output.txt
cat output.txt
file1.txt
file2.txt
output.txt (8 Replies)