I need your help in finding out users not logged in to linux system for more than 90 days. I found a script from our forum i am getting error while using that.
from the code i have debugged line by line to see where i am getting the problem. i found out the below line i am getting error. I have provided the error details below.
Pleae help me and let me know If there is any other find the users notlogged in for more that 90days . FYI: I have around 250 users. for some users last command returns null.
I have attached script in which i did slight modification
Hi,
Can I get a script to list out all the users, who has not logged on since last 90 days. Last command in not working due due to /var/adm/wtmpx is more than 2 GB.
Thanks in advance.
Regards,
Roni (10 Replies)
Hi,
Here is the script that I have written to check if a particular user is has logged out, and if yes, then a mail needs to be sent to the management the details of whatever has been captured by the script command.
echo "The current users are:"
who | awk '{print $1}' | sort > temp1
cp... (1 Reply)
Hi All,
I am trying to write a script to get the user information & the command executed.
I tried something like this :
w | sort | awk '{print$5$6$7}'
My requirement is to identify the users who execute the same command at same time.
I need the user name & the... (2 Replies)
My admin needs a shell script in Korn that will show conditions based on users logged in. I have never used the Korn shell and have no clue what I am doing, can anyone help.
here are the conditions that need to be returned.
if users are below 5
displays should be: performance is high
if... (1 Reply)
For the first 4 users only that are currently logged in output their effective user id.
It's not important the order in which each logged in i just want to have the top 4.
Same question as here...... (0 Replies)
Hi,
How to find the users who did not login into a UNIX box (thru ssh/ftp or any other way) for last 90 days?
I think of using "finger" or "last" command to findout each user's last login and then find number of days between today and that day. Is there any other better way or anyone prepared... (1 Reply)
Discussion started by: reddyr
1 Replies
LEARN ABOUT DEBIAN
time.conf
TIME.CONF(5) Linux-PAM Manual TIME.CONF(5)NAME
time.conf - configuration file for the pam_time module
DESCRIPTION
The pam_time PAM module does not authenticate the user, but instead it restricts access to a system and or specific applications at various
times of the day and on specific days or over various terminal lines. This module can be configured to deny access to (individual) users
based on their name, the time of day, the day of week, the service they are applying for and their terminal from which they are making
their request.
For this module to function correctly there must be a correctly formatted /etc/security/time.conf file present. White spaces are ignored
and lines maybe extended with '' (escaped newlines). Text following a '#' is ignored to the end of the line.
The syntax of the lines is as follows:
services;ttys;users;times
In words, each rule occupies a line, terminated with a newline or the beginning of a comment; a '#'. It contains four fields separated with
semicolons, ';'.
The first field, the services field, is a logic list of PAM service names that the rule applies to.
The second field, the tty field, is a logic list of terminal names that this rule applies to.
The third field, the users field, is a logic list of users or a netgroup of users to whom this rule applies.
For these items the simple wildcard '*' may be used only once. With netgroups no wildcards or logic operators are allowed.
The times field is used to indicate the times at which this rule applies. The format here is a logic list of day/time-range entries. The
days are specified by a sequence of two character entries, MoTuSa for example is Monday Tuesday and Saturday. Note that repeated days are
unset MoMo = no day, and MoWk = all weekdays bar Monday. The two character combinations accepted are Mo Tu We Th Fr Sa Su Wk Wd Al, the
last two being week-end days and all 7 days of the week respectively. As a final example, AlFr means all days except Friday.
Each day/time-range can be prefixed with a '!' to indicate "anything but". The time-range part is two 24-hour times HHMM, separated by a
hyphen, indicating the start and finish time (if the finish time is smaller than the start time it is deemed to apply on the following
day).
For a rule to be active, ALL of service+ttys+users must be satisfied by the applying process.
Note, currently there is no daemon enforcing the end of a session. This needs to be remedied.
Poorly formatted rules are logged as errors using syslog(3).
EXAMPLES
These are some example lines which might be specified in /etc/security/time.conf.
All users except for root are denied access to console-login at all times:
login ; tty* & !ttyp* ; !root ; !Al0000-2400
Games (configured to use PAM) are only to be accessed out of working hours. This rule does not apply to the user waster:
games ; * ; !waster ; Wd0000-2400 | Wk1800-0800
SEE ALSO pam_time(8), pam.d(5), pam(7)AUTHOR
pam_time was written by Andrew G. Morgan <morgan@kernel.org>.
Linux-PAM Manual 06/04/2011 TIME.CONF(5)