Hi All,
I need to pass a variable to perl script from bash script, where in perl i am using if condition. Here is the cmd what i am using in perl
FROM_DATE="06/05/2008"
TO_DATE="07/05/2008"
"perl -ne ' print if ( $_ >="$FROM_DATE" && $_ <= "$TO_DATE" ) ' filename"
filename has... (10 Replies)
I am trying to use a script to replace the header of each file, whose filename are stored within the array $test, using the sed command within a Perl script as follows:
$count = 0;
while ( $count < $#test )
{
`sed -e 's/BIOGRF 321/BIOGRF 332/g' ${test} > 0`;
`cat 0 >... (2 Replies)
I am fiddling with a little script that will issue a shutdown command if the temperature on the CPU goes above a certain level. I started writing the script in Bash, and then thought I would like to use Perl to extract the detailed bits, but I am not sure if this is really practical. Basically I... (2 Replies)
Hi Everyone,
i have a string 00:44:40
so:
$tmp=~ s/://gi;
$tmp=~s/({2})({2})({2})/$1*3600+$2*60+$3/e;
the output is 2680.
Any way to combine this two lines into a single line?
Thanks (4 Replies)
Hi,
I have tried several times but failed, I need to call this script from the perl script. This one line script will be sent to /var/tmp/error
Bash command:
/usr/openv/netbackup/bin/admincmd/bperror -backstat -l -hoursago 12 |awk '{ print $19, $12, $14, $16}'|grep -vi default|sort >... (12 Replies)
so in unix this command works works and shows me a list of directories
find . -name \*.xls -exec dirname {} \; | sort -u | > list.txt
but when i try running a perl script to run this command
my $query = 'find . -name \*.xls -exec dirname {} \; | sort -u | > list.txt';... (2 Replies)
Server: IBM p770
OS: AIX 6.1 TL5 SP1
When one of our develoeprs types "bash" on the command line to switch shells, it hangs. For some reason, two bash processes are created....the first bash process spawns a second bash process in the same console, causing a hang. Anyone have any idea what... (2 Replies)
I'm reading about debugging aids in bash and have come across the set command. It says in my little book that an addition to typing
set
you can also use them "on the command line when running a script..." and it lists this in a small table:
set -o option Command Line... (5 Replies)
In a bash script, one can call a perl command in the following manner, where "myperlcommand" is a perl command.
perl -e 'myperlcommand(arguments)'
perl -e 'print("UUUU"x4)'
Now, how can one call a bash command from within a perl script? (Suppose that mybashcommand is a bash... (1 Reply)
How to run several bash commands put in bash command line without needing and requiring a script file.
Because I'm actually a windows guy and new here so for illustration is sort of :
$ bash "echo ${PATH} & echo have a nice day!"
will do output, for example:... (4 Replies)
Discussion started by: abdulbadii
4 Replies
LEARN ABOUT OSX
base64
base64(1) BSD General Commands Manual base64(1)NAME
base64 -- Encode and decode using Base64 representation
SYNOPSIS
base64 [-d | -h | -v | -D] [-b count] [-i input_file] [-o output_file]
DESCRIPTION
base64 encodes and decodes Base64 data, as specified in RFC 4648. With no options, base64 reads raw data from stdin and writes encoded data
as a continuous block to stdout.
OPTIONS
The following options are available:
-b count
--break=count Insert line breaks every count characters. Default is 0, which generates an unbroken stream.
-d
--debug Print verbose log messages during processing.
-D
--decode Decode incoming Base64 stream into binary data.
-h
--help Print usage summary and exit.
-i input_file
--input=input_file Read input from input_file. Default is stdin; passing - also represents stdin.
-o output_file
--output=output_file
Write output to output_file. Default is stdout; passing - also represents stdout.
-v
--version Print build version and exit.
SEE ALSO openssl(1), wikipedia page <http://en.wikipedia.org/wiki/Base64>, RFC 4648 <http://tools.ietf.org/html/rfc4648>
Mac OS X 10.7 February 8, 2011 Mac OS X 10.7