Calling bash script works when called manually but not via Cron?
Hi, I've got a Bash backup script I'm trying to run on a directory via a cron job nightly. If I ssh in and run the script manually it works flawlessly. If I set up the cron to run evertything is totally messed up I don't even know where to begin.
Basically the path structure is
/home/username/domainname.com/_mybash.sh
where I'm trying to backup domainname.com
If I ssh in and go cd domainname.com and then sh _mybash.sh from the command line. The script runs fine. If I set up a cron to /home/username/domainname.com/_mybash.sh the script runs and attempts to backup everything under username... I don't understand.
Hi all,
I have a main script (called OracleCleanup) that runs some sql queries. that runs off a wrapper script which contains the sources for the login information and and JOB_HOME (the script is below). When I schedule this job in the cron the log says that it cannot open my list file, which... (4 Replies)
I've got a ksh script that works like a charm when I run it manually. When I set it up in a cron, I keep getting this error in my log:
syntax error at line 90: `$' unexpected
Here's my snippet of code starting at line 90:
while ]
do
sleep 900
done
What's the... (5 Replies)
Hey all,
Just wanted to get some input on a script I am using to import files into a MySQL database.
The process is pretty simple: my main server exports these files and FTPs them. I have a script that FTPs them to the machine running that runs this script. The FTP script runs without issue... (2 Replies)
How do i get the value of the variable from the called script(script2) to the calling script(script1) in ksh ?
I've given portion of the script here to explain the problem.
Portion of Script 1
=============
-----
-----
tmp=`a.ksh p1 p2 p3`
if then
# error processing
fi
-----... (10 Replies)
Hi all,
I have two ksh scripts
#sample1.sh
#!/bin/ksh
. ./sample2.sh
echo $fileExist
#sample2.sh
#!/bin/ksh
func()
{
i=1
return $a
}
func
echo $?
Here how should I return the value of sample2.sh back to sample1.sh?
Thanks in advance. (2 Replies)
Hi,
I am building a web interface to run a series of shell scripts that reside on the web server. The bash script are written such that they can be used independently for the task they are meant for, or the same scripts can be run from this web UI. The scripts are mostly for doing software... (1 Reply)
Hi,
My shell script not getting called through cron job.
The same works fine when executed manually.
I tried to generate logs to find if the scripts has some errors related to path using following command- trying to execute .sh file every 5 mins:
*/5 * * * * /home/myfolder/abc.sh... (17 Replies)
Hello gurus,
I am making what I think is a simple db2 call from within a shell script but I am having difficulty producing the desired
report when I run the script shown below from a shell script in cron. For example, my script and the crontab file setup
is shown below:
#!/bin/ksh
db2... (3 Replies)
Hi,
I "borrowed" a script I found online, to start a SAP router application on a Solaris 11 (SPARC) server.
The script runs fine when calling it manually, but when I schedule it to run from cron, it doesn't. I don't see any warning or failure messages anywhere, just nothing happens.
... (11 Replies)
Discussion started by: bredman
11 Replies
LEARN ABOUT CENTOS
crontabs
CRONTABS(4) Crontabs users' Manual CRONTABS(4)NAME
crontabs - configuration and scripts for running periodical jobs
SYNOPSIS
run-parts [--list|--test]<directory>
DESCRIPTION
Crontabs is a historical name for the run-parts script and the system crontab. The run-parts script runs all executables in the specified
directory. Run-parts runs all executables in the specified directory. The execution of files can be allowed or denied by creating file
jobs.allow or jobs.deny which worked similar as other allow/deny config files. The file must be created in the specified directory.
--list print names of all files (not limited to executables), but don't run them. This option can't be used with test option.
--test print names of files, which would be run.
Randomization of jobs can be configured in the /etc/sysconfig/run-parts file. To enable randomization of jobs, set the RANDOMIZE
parameter to 1 and set the RANDOM parameter to an integer which determines a random seed. Additionally, you may configure the RAN-
DOMTIME parameter (again, by specifying an integer) to provide an additional level of randomization. Jobs are not randomized when
the RANDOM and RANDOMTIME parameters are set to 0. Values in these two parameters must be set to 1 or larger to provide a good
enough randomization.
Randomization of cron jobs can be useful for shared networks, where multiple cron jobs executed at once can cause spikes in traffic,
especially during daily jobs. With randomized jobs, the workload is evenly distributed throughout the day.
EXAMPLE OF CONFIGURATION FILE
RANDOMIZE=1
RANDOM=4
RANDOMTIME=8
Historically the crontab file contained configuration which called run-parts on files in cron.{daily,weekly,monthly} directories. These
jobs are now run indirectly through anacron to prevent conflicts between cron and anacron. That means the anacron package has to be
installed if the jobs in these directories should be running. Refer to the anacron(8) how to limit the time of day of the job execution.
EXAMPLE
/etc/cron.daily/jobs.deny could contain for example 0logwatch which forbid execution of this script.
SEE ALSO anacron(8), crontab(5)Marcela Malaova 2012-08-29 CRONTABS(4)