Calling bash script works when called manually but not via Cron?
Hi, I've got a Bash backup script I'm trying to run on a directory via a cron job nightly. If I ssh in and run the script manually it works flawlessly. If I set up the cron to run evertything is totally messed up I don't even know where to begin.
Basically the path structure is
/home/username/domainname.com/_mybash.sh
where I'm trying to backup domainname.com
If I ssh in and go cd domainname.com and then sh _mybash.sh from the command line. The script runs fine. If I set up a cron to /home/username/domainname.com/_mybash.sh the script runs and attempts to backup everything under username... I don't understand.
Hi all,
I have a main script (called OracleCleanup) that runs some sql queries. that runs off a wrapper script which contains the sources for the login information and and JOB_HOME (the script is below). When I schedule this job in the cron the log says that it cannot open my list file, which... (4 Replies)
I've got a ksh script that works like a charm when I run it manually. When I set it up in a cron, I keep getting this error in my log:
syntax error at line 90: `$' unexpected
Here's my snippet of code starting at line 90:
while ]
do
sleep 900
done
What's the... (5 Replies)
Hey all,
Just wanted to get some input on a script I am using to import files into a MySQL database.
The process is pretty simple: my main server exports these files and FTPs them. I have a script that FTPs them to the machine running that runs this script. The FTP script runs without issue... (2 Replies)
How do i get the value of the variable from the called script(script2) to the calling script(script1) in ksh ?
I've given portion of the script here to explain the problem.
Portion of Script 1
=============
-----
-----
tmp=`a.ksh p1 p2 p3`
if then
# error processing
fi
-----... (10 Replies)
Hi all,
I have two ksh scripts
#sample1.sh
#!/bin/ksh
. ./sample2.sh
echo $fileExist
#sample2.sh
#!/bin/ksh
func()
{
i=1
return $a
}
func
echo $?
Here how should I return the value of sample2.sh back to sample1.sh?
Thanks in advance. (2 Replies)
Hi,
I am building a web interface to run a series of shell scripts that reside on the web server. The bash script are written such that they can be used independently for the task they are meant for, or the same scripts can be run from this web UI. The scripts are mostly for doing software... (1 Reply)
Hi,
My shell script not getting called through cron job.
The same works fine when executed manually.
I tried to generate logs to find if the scripts has some errors related to path using following command- trying to execute .sh file every 5 mins:
*/5 * * * * /home/myfolder/abc.sh... (17 Replies)
Hello gurus,
I am making what I think is a simple db2 call from within a shell script but I am having difficulty producing the desired
report when I run the script shown below from a shell script in cron. For example, my script and the crontab file setup
is shown below:
#!/bin/ksh
db2... (3 Replies)
Hi,
I "borrowed" a script I found online, to start a SAP router application on a Solaris 11 (SPARC) server.
The script runs fine when calling it manually, but when I schedule it to run from cron, it doesn't. I don't see any warning or failure messages anywhere, just nothing happens.
... (11 Replies)
Discussion started by: bredman
11 Replies
LEARN ABOUT PHP
datefmt_set_lenient
DATEFMT_SET_LENIENT(3) 1 DATEFMT_SET_LENIENT(3)IntlDateFormatter::setLenient - Set the leniency of the parser
Object oriented style
SYNOPSIS
public bool IntlDateFormatter::setLenient (bool $lenient)
DESCRIPTION
Procedural style
bool datefmt_set_lenient (IntlDateFormatter $fmt, bool $lenient)
Define if the parser is strict or lenient in interpreting inputs that do not match the pattern exactly. Enabling lenient parsing allows
the parser to accept otherwise flawed date or time patterns, parsing as much as possible to obtain a value. Extra space, unrecognized
tokens, or invalid values ("February 30th") are not accepted.
PARAMETERS
o $fmt
- The formatter resource
o $lenient
- Sets whether the parser is lenient or not, default is TRUE (lenient).
RETURN VALUES
Returns TRUE on success or FALSE on failure.
EXAMPLES
Example #1
datefmt_set_lenient(3) example
<?php
$fmt = datefmt_create(
'en_US',
IntlDateFormatter::FULL,
IntlDateFormatter::FULL,
'America/Los_Angeles',
IntlDateFormatter::GREGORIAN,
'dd/MM/yyyy'
);
echo 'lenient of the formatter is : ';
if ($fmt->isLenient()) {
echo 'TRUE';
} else {
echo 'FALSE';
}
datefmt_parse($fmt, '35/13/1971');
echo "
Trying to do parse('35/13/1971').
Result is : " . datefmt_parse($fmt, '35/13/1971');
if (intl_get_error_code() != 0) {
echo "
Error_msg is : " . intl_get_error_message();
echo "
Error_code is : " . intl_get_error_code();
}
datefmt_set_lenient($fmt, false);
echo "
Now lenient of the formatter is : ";
if ($fmt->isLenient()) {
echo 'TRUE';
} else {
echo 'FALSE';
}
datefmt_parse($fmt, '35/13/1971');
echo "
Trying to do parse('35/13/1971').
Result is : " . datefmt_parse($fmt, '35/13/1971');
if (intl_get_error_code() != 0) {
echo "
Error_msg is : ".intl_get_error_message();
echo "
Error_code is : ".intl_get_error_code();
}
?>
Example #2
OO example
<?php
$fmt = new IntlDateFormatter(
'en_US',
IntlDateFormatter::FULL,
IntlDateFormatter::FULL,
'America/Los_Angeles',
IntlDateFormatter::GREGORIAN,
'dd/MM/yyyy'
);
echo 'lenient of the formatter is : ';
if ($fmt->isLenient()) {
echo 'TRUE';
} else {
echo 'FALSE';
}
$fmt->parse('35/13/1971');
echo "
Trying to do parse('35/13/1971').
Result is : " . $fmt->parse('35/13/1971');
if (intl_get_error_code() != 0) {
echo "
Error_msg is : " . intl_get_error_message();
echo "
Error_code is : " . intl_get_error_code();
}
$fmt->setLenient(FALSE);
echo "
Now lenient of the formatter is : ";
if ($fmt->isLenient()) {
echo 'TRUE';
} else {
echo 'FALSE';
}
$fmt->parse('35/13/1971');
echo "
Trying to do parse('35/13/1971').
Result is : " . $fmt->parse('35/13/1971');
if (intl_get_error_code() != 0) {
echo "
Error_msg is : " . intl_get_error_message();
echo "
Error_code is : " . intl_get_error_code();
}
?>
The above example will output:
lenient of the formatter is : TRUE
Trying to do parse('35/13/1971').
Result is : 66038400
Now lenient of the formatter is : FALSE
Trying to do parse('35/13/1971').
Result is :
Error_msg is : Date parsing failed: U_PARSE_ERROR
Error_code is : 9
SEE ALSO datefmt_is_lenient(3), datefmt_create(3).
PHP Documentation Group DATEFMT_SET_LENIENT(3)