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Full Discussion: Print rows with value zero or less than zero using awk
Top Forums Shell Programming and Scripting Print rows with value zero or less than zero using awk Post 302938044 by kumaran_5555 on Wednesday 11th of March 2015 01:28:57 PM
Old 03-11-2015
Still ambiguous, this is how i understand

1. ignore header
2. space as seperator
3. print rows which has any column as zero
Code:
awk 'FNR>1{for(i=1;i<=NF;i++){ if($i==0){print ; next; } }}' fileName.txt

 

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LEARN ABOUT DEBIAN

pfscut

pfscut(1)						      General Commands Manual							 pfscut(1)

NAME

       pfscut - Extract a rectangle out of a frame in PFS stream

SYNOPSIS

       pfscut [--left <columns>] [--right <columns>] [--top <rows>] [--bottom <rows>] [--width <new_width>] [--height <new_height>] [--help] [x_ul
       y_ul x_br y_br]

DESCRIPTION

       Extract a rectangle out of each frame in PFS stream. You can either specify x and y coordinates of upper left and lower right  corner  (the
       coordinates start with 0 and rise in the left-to-right and up-to-botton directions) or give a combination of the options listed below.

OPTIONS

       --left <columns>, -l <columns>
	      Number of columns to be cut out from the left edge of an image.

       --right <columns>, -r <columns>
	      Number of columns to be cut out from the right edge of an image.

       --top <rows>, -t <rows>
	      Number of rows to be cut out from the top edge of an image.

       --bottom <rows>, -b <rows>
	      Number of rows to be cut out from the bottom edge of an image.

       --width <new_width>, -W <new_width>
	      Width of an output image. Note that --width can be mixed with either --left or --right option.

       --height <new_height>, -H <new_height>
	      Height of an output image. Note that --height can be mixed with either --top or --bottom option.

       --help, -h
	      Print a list of commandline options.

EXAMPLES

       pfsin image.hdr | pfscut --left 20 --top 5 | pfsout out.hdr
	      Cut out 20 columns from the left and 5 rows from the top edge of image.hdr and save frame as out.hdr.

       pfsin image.hdr | pfscut --left 20 --width 400 | pfsout out.hdr
	      Cut out 20 columns from the left edge of image.hdr, and create output image 400 pixels in width.

       pfsin image.hdr | pfscut 0 0 511 511 | pfsout out.hdr
	      Cut  left-upper  part  of  the  image of the size 512x512 (note that coordinates start with 0 and 512 is the last row/column that is
	      included in the resulting image).

       SEE ALSO
	      pfsin(1) pfsout(1)

BUGS

       Please report bugs and comments to Dorota Zdrojewska <dzdrojewska@wi.ps.pl>.

																	 pfscut(1)
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