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Top Forums Shell Programming and Scripting Adding an element to a bash array with a variable Post 302937953 by Chubler_XL on Tuesday 10th of March 2015 11:39:37 PM
Old 03-11-2015
This seems to be working fine for me:

Code:
$ CMD_STRING='-L 22 -s 0 -r -O -A i -N 100 -n'
$ CMD_STRING_LIST=(1 2 3)
$ CMD_STRING_LIST=("${CMD_STRING_LIST[@]}" "$CMD_STRING")
$ echo ${#CMD_STRING_LIST[@]}
4
$ echo ${CMD_STRING_LIST[3]}
-L 22 -s 0 -r -O -A i -N 100 -n

I wonder if your doing this all within a loop and loosing the changes due to Bash sub-shell: variables lost
This User Gave Thanks to Chubler_XL For This Post:
 

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PARSE_STR(3)								 1							      PARSE_STR(3)

parse_str - Parses the string into variables

SYNOPSIS
void parse_str (string $str, [array &$arr]) DESCRIPTION
Parses $str as if it were the query string passed via a URL and sets variables in the current scope. Note To get the current QUERY_STRING, you may use the variable $_SERVER['QUERY_STRING']. Also, you may want to read the section on vari- ables from external sources. Note The magic_quotes_gpc setting affects the output of this function, as parse_str(3) uses the same mechanism that PHP uses to populate the $_GET, $_POST, etc. variables. PARAMETERS
o $str - The input string. o $arr - If the second parameter $arr is present, variables are stored in this variable as array elements instead. RETURN VALUES
No value is returned. EXAMPLES
Example #1 Using parse_str(3) <?php $str = "first=value&arr[]=foo+bar&arr[]=baz"; parse_str($str); echo $first; // value echo $arr[0]; // foo bar echo $arr[1]; // baz parse_str($str, $output); echo $output['first']; // value echo $output['arr'][0]; // foo bar echo $output['arr'][1]; // baz ?> SEE ALSO
parse_url(3), pathinfo(3), http_build_query(3), get_magic_quotes_gpc(3), urldecode(3). PHP Documentation Group PARSE_STR(3)
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