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Top Forums Shell Programming and Scripting Get min and max value in column Post 302934606 by RavinderSingh13 on Monday 9th of February 2015 08:13:05 AM
Old 02-09-2015
Hello jiam912,

Could you please try following and let me know if this helps.
Code:
wk '{A[substr($0,1,5)+0]=A[substr($0,1,5)+0]>=substr($0,6)+0?A[substr($0,1,5)+0]:substr($0,6)+0;B[substr($0,1,5)+0]=B[substr($0,1,5)+0]<=substr($0,6)+0 && B[substr($0,1,5)+0]?B[substr($0,1,5)+0]:substr($0,6)} END{print "MAX values:";for(i in A){print i OFS A[i]};print "MIN values:";for(j in B){print j OFS B[j]}}' Input_file

Output is as follows.
Code:
MAX values:
51000 10012
51020 10012
MIN values:
51000 10002
51020 10002

EDIT: You can try following also to get output in requested form.
Code:
awk '{A[substr($0,1,5)+0]=A[substr($0,1,5)+0]>=substr($0,6)+0?A[substr($0,1,5)+0]:substr($0,6)+0;B[substr($0,1,5)+0]=B[substr($0,1,5)+0]<=substr($0,6)+0 && B[substr($0,1,5)+0]?B[substr($0,1,5)+0]:substr($0,6)} END{print "VALUE MAX MIN";for(i in A){print i OFS A[i] OFS B[i]}}' OFS="\t"  Input_file

EDIT: Adding a nonone liner form of solution.
Code:
awk '{
          A[substr($0,1,5)+0]=A[substr($0,1,5)+0]>=substr($0,6)+0?A[substr($0,1,5)+0]:substr($0,6)+0;
          B[substr($0,1,5)+0]=B[substr($0,1,5)+0]<=substr($0,6)+0 && B[substr($0,1,5)+0]?B[substr($0,1,5)+0]:substr($0,6)
       }
END {
          print "VALUE MAX MIN";
          for(i in A)
       {
          print i OFS A[i] OFS B[i]
       }
       }
    ' OFS="\t"  Input_file

Output will be as follows.
Code:
VALUE MAX MIN
51000 10012 10002
51020 10012 10002


Thanks,
R. Singh

Last edited by RavinderSingh13; 02-09-2015 at 09:26 AM.. Reason: Added one more solution now + added one liner form of solution now
This User Gave Thanks to RavinderSingh13 For This Post:
 

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