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Top Forums Shell Programming and Scripting awk if condition match and print all Post 302934308 by horsepower on Friday 6th of February 2015 05:35:48 AM
Old 02-06-2015
awk if condition match and print all

Hi, I am trying to do something like this ...
I use awk to match a pattern, and then print out all col.
My code is :
Code:
awk '{if ($1 ==300) print $1,$2-'$sbin7',$3}' tmp.txt

output=
Code:
300 2

whereby sbin7=2,

The thing is, I want to print all col and row, not just the matched line/row only, but I still want to make the change once pattern match.
I want to print out something like this:
Code:
10 6
300 2
303 1


any chance ? Smilie

tmp.txt content:
Code:
10 6
300 4
303 1


Last edited by Franklin52; 02-06-2015 at 07:55 AM.. Reason: Please use code tags
 

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GREP(1) 						      General Commands Manual							   GREP(1)

NAME
grep - search a file for lines containing a given pattern SYNOPSIS
grep [-elnsv] pattern [file] ... OPTIONS
-e -e pattern is the same as pattern -c Print a count of lines matched -i Ignore case -l Print file names, no lines -n Print line numbers -s Status only, no printed output -v Select lines that do not match EXAMPLES
grep mouse file # Find lines in file containing mouse grep [0-9] file # Print lines containing a digit DESCRIPTION
Grep searches one or more files (by default, stdin) and selects out all the lines that match the pattern. All the regular expressions accepted by ed and mined are allowed. In addition, + can be used instead of * to mean 1 or more occurrences, ? can be used to mean 0 or 1 occurrences, and | can be used between two regular expressions to mean either one of them. Parentheses can be used for grouping. If a match is found, exit status 0 is returned. If no match is found, exit status 1 is returned. If an error is detected, exit status 2 is returned. SEE ALSO
cgrep(1), fgrep(1), sed(1), awk(9). GREP(1)
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