Hi
All,
I have oracle 9i and 10g on unix. now i have 920.env and 1020.en file to set p respective enviornment.
when I excecute this commnad
. $HOME/920.env from the shell prompt it is working fine. and also same for 1020.env .
Now same command . $HOME/920.env i am putting in shell... (2 Replies)
Trying to figure out why this works:
printpwd.pl
#!/usr/bin/perl
use CGI::Carp qw( fatalsToBrowser );
print "Content-type: text/html\n\n";
$A = system("pwd");
$A = `pwd`;
print "$A\n";
^^actually that works/breaks if that makes any sense.. i get the working directory twice but when... (5 Replies)
Hi All,
I have writtern a shell script which has a sql query. I want to send the results of sql query to a shared area over a network.I also want to log the errors in a log file if the text file is not sent to shared area.
The results of sql query are spooled in TEMPFILE.
LOGFILE... (1 Reply)
i wrote a shell program in Home Directory.
and i changed to other directory.
i want to try to execute shell script in Other Dir.
it is not executed.
how can i make this script to execute in other directory also??
Thanks,
Arun (11 Replies)
Shell Scipt: temp.sh
su - <$username>
expect pass.exp
Expect script: pass.exp
#!/usr/bin/expect -f
# Login
#######################
expect "Password: " send "<$password>\r"
it comes up with Password: but doesnt take password passed throguh file. (2 Replies)
loop=y
while
do
clear
tput cup 5 15
echo -n "People Database"
echo -n "===================================="
tput cup 8 12
echo -n "L-Print Last Names"
tput cup 9 12
echo -n "F-Print First NAmes"
tput cup 10 12
echo -n "C-Print First Name, Last Name sorted by city"
tput cup 11 12... (3 Replies)
Dear All,
I have script.
Dest=""
IFS='
'
for translation in $(echo $MY_MAP)
do
t1=$(echo $translation | cut -d"=" -f1)
t2=$(echo $translation | cut -d"=" -f2| cut -d"," -f1)
if
then
Dest=$UNX/$u_product_path/$u_study_path/$UNXTR/$t2
break;
... (4 Replies)
Hi Guys,
I have one installer shell script which normally get from the dev team to install the app and it works fine for years (in IAX) the same installer/script iam trying to run in Linux 7.2 but it stuck somewhere which I cannot debug, can you help me to point out where it stuck .
here is the... (9 Replies)
Student just starting to learn shell script
I have file named
smallFile
John:Doe:ECE:3.54:doe@jd.home.org:111.222.3333
James:Davis:ECE:3.71:davis@jd.work.org:111.222.1111
Al:Davis:CS:2.63:davis@a.lakers.org:111.222.2222
Ahmad:Rashid:MBA:3.74:ahmad@mba.org:111.222.4444... (2 Replies)
Discussion started by: jetoutant
2 Replies
LEARN ABOUT PHP
datetime.sub
DATETIME.SUB(3) 1 DATETIME.SUB(3)DateTime::sub - Subtracts an amount of days, months, years, hours, minutes and seconds from a DateTime object
Object oriented style
SYNOPSIS
public DateTime DateTime::sub (DateInterval $interval)
DESCRIPTION
Procedural style
DateTime date_sub (DateTime $object, DateInterval $interval)
Subtracts the specified DateInterval object from the specified DateTime object.
PARAMETERS
o $object
-Procedural style only: A DateTime object returned by date_create(3). The function modifies this object.
o $interval
- A DateInterval object
RETURN VALUES
Returns the DateTime object for method chaining or FALSE on failure.
EXAMPLES
Example #1
DateTime.sub(3) example
Object oriented style
<?php
$date = new DateTime('2000-01-20');
$date->sub(new DateInterval('P10D'));
echo $date->format('Y-m-d') . "
";
?>
Procedural style
<?php
$date = date_create('2000-01-20');
date_sub($date, date_interval_create_from_date_string('10 days'));
echo date_format($date, 'Y-m-d');
?>
The above examples will output:
2000-01-10
Example #2
Further DateTime.sub(3) examples
<?php
$date = new DateTime('2000-01-20');
$date->sub(new DateInterval('PT10H30S'));
echo $date->format('Y-m-d H:i:s') . "
";
$date = new DateTime('2000-01-20');
$date->sub(new DateInterval('P7Y5M4DT4H3M2S'));
echo $date->format('Y-m-d H:i:s') . "
";
?>
The above example will output:
2000-01-19 13:59:30
1992-08-15 19:56:58
Example #3
Beware when subtracting months
<?php
$date = new DateTime('2001-04-30');
$interval = new DateInterval('P1M');
$date->sub($interval);
echo $date->format('Y-m-d') . "
";
$date->sub($interval);
echo $date->format('Y-m-d') . "
";
?>
The above example will output:
2001-03-30
2001-03-02
NOTES DateTime.modify(3) is an alternative when using PHP 5.2.
SEE ALSO DateTime.add(3), DateTime.diff(3), DateTime.modify(3).
PHP Documentation Group DATETIME.SUB(3)