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Full Discussion: Rounding off a decimal
Top Forums UNIX for Dummies Questions & Answers Rounding off a decimal Post 302931857 by SanjayKumar28 on Friday 16th of January 2015 04:15:38 AM
Old 01-16-2015
Thanks for your reply Ravinder. But, I need to round off the decimal to higher interger i.e to 5 and not to 4. Also, I need the result using the ceil command.
 

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CEIL(3) 						     Linux Programmer's Manual							   CEIL(3)

NAME
ceil, ceilf, ceill - ceiling function: smallest integral value not less than argument SYNOPSIS
#include <math.h> double ceil(double x); float ceilf(float x); long double ceill(long double x); DESCRIPTION
These functions round x up to the nearest integer. RETURN VALUE
The rounded integer value. If x is integral or infinite, x itself is returned. ERRORS
No errors other than EDOM and ERANGE can occur. If x is NaN, then NaN is returned and errno may be set to EDOM. NOTES
SUSv2 and POSIX 1003.1-2001 contain text about overflow (which might set errno to ERANGE, or raise an exception). In practice, the result cannot overflow on any current machine, so this error-handling stuff is just nonsense. (More precisely, overflow can happen only when the maximum value of the exponent is smaller than the number of mantissa bits. For the IEEE-754 standard 32-bit and 64-bit floating point num- bers the maximum value of the exponent is 128 (resp. 1024), and the number of mantissa bits is 24 (resp. 53).) CONFORMING TO
The ceil() function conforms to SVID 3, POSIX, BSD 4.3, ISO 9899. The other functions are from C99. SEE ALSO
floor(3), lrint(3), nearbyint(3), rint(3), round(3), trunc(3) 2001-05-31 CEIL(3)
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