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Top Forums Shell Programming and Scripting How to find the job outside the box? Post 302930998 by RavinderSingh13 on Friday 9th of January 2015 10:17:53 AM
Old 01-09-2015
Quote:
Originally Posted by ken6503
Thanks Singh for your reply.

the ways you provied work fine.
my goal is to compare the found and not found job and list the jobs that is in found but not in not_found. in above case I want to get below out put

Code:
 
sname-pname-cprexhaa
sname-pname-cprexloa
sname-pname-cprexmta
sname-pname-cprexrga
sname-pname-abcd-phase

is it possible to achieve this within same command?
thanks in advance
Hello Ken6503,

Following may help you in same.
Code:
awk '/^s\(s/{sub(/^s\(/,X,$0);sub(/\)$/,Y,$0);A[$0]=$0;next} !/^s\(s/{B[$0]} END{for(j in B){W=B[j];for(W in A){delete A[j]}};for(u in A){print A}}' Input_file

Output will be as follows.
Code:
sname-pname-cprexhaa
sname-pname-abcd-phase
sname-pname-cprexrga
sname-pname-cprexloa
sname-pname-cprexmta

EDIT: Adding non oneliner command for same.
Code:
awk '/^s\(s/{
                sub(/^s\(/,X,$0);
                sub(/\)$/,Y,$0);
                A[$0]=$0;
                next
            }
     !/^s\(s/{
                B[$0]
             }
    END{
                for(j in B){
                                W=B[j];
                                for(W in A){
                                                  delete A[j]
                                           }
                           };
                for(u in A){
                                print A[u]
                           }
        }
     '  Input_file


Thanks,
R. Singh

Last edited by RavinderSingh13; 01-09-2015 at 11:41 AM.. Reason: Added non one liner form of code
This User Gave Thanks to RavinderSingh13 For This Post:
 

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