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Full Discussion: Calculate given date - 1 day
Top Forums Shell Programming and Scripting Calculate given date - 1 day Post 302930743 by RavinderSingh13 on Tuesday 6th of January 2015 11:34:25 PM
Old 01-07-2015
Hello kmanivan82,

Kindly use code tags always for codes/commands/Inputs you are providing in your posts as per forum rules. Following may help you in same.
Code:
cat date_check1.ksh
echo $1 | awk -vs1="01" -vs2="03" -vs3="12" '{
                                                if(length($0)>8){
                                                                        print "Wrong Input!!";
                                                                        exit
                                                                }
                                                YEAR=substr($0,1,4);
                                                YEAR+0;
                                                MONTH=substr($0,5,2);
                                                MONTH+0;
                                                DATE=substr($0,7,2);
                                                DATE+0;
                                                split("31 29 31 30 31 30 31 31 30 31 30 31", W," ");
                                                if(DATE==s1 && MONTH==s1){
                                                                                YEAR=YEAR-1;
                                                                                MONTH=12;
                                                                                DATE=31;
                                                                                print YEAR MONTH DATE
                                                                         }
                                                else if(DATE==s1 && MONTH >= s1 && MONTH <= s3){
                                                                                MONTH=MONTH-1;
                                                                                W[2]=(YEAR%4!=0)?28:29;
                                                                                print YEAR MONTH W[MONTH]
                                                                                                }
                                                else {
                                                                                DATE=DATE-1;
                                                                                printf("%04d%02d%02d\n", YEAR, MONTH, DATE);
                                                     }
                                              }'

When we run code it will show output as follows.
Code:
./date_check1.ksh 20150106
20150105

EDIT: Adding one liner form for same.
Code:
cat date_check.ksh
echo $1 | awk -vs1="01" -vs2="03" -vs3="12" '{if(length($0)>8){print "Wrong Input!!";exit};YEAR=substr($0,1,4);YEAR+0;MONTH=substr($0,5,2);MONTH+0;DATE=substr($0,7,2);DATE+0;split("31 29 31 30 31 30 31 31 30 31 30 31", W," ");if(DATE==s1 && MONTH==s1){YEAR=YEAR-1; MONTH=12; DATE=31; print YEAR MONTH DATE}  else if(DATE==s1 && MONTH >= s1 && MONTH <= s3){MONTH=MONTH-1;W[2]=(YEAR%4!=0)?28:29;print YEAR MONTH W[MONTH]} else {DATE=DATE-1;printf("%04d%02d%02d\n", YEAR, MONTH, DATE)}}'


Thanks,
R. Singh

Last edited by RavinderSingh13; 01-07-2015 at 12:58 AM.. Reason: added a note + added a one liner form of code
This User Gave Thanks to RavinderSingh13 For This Post:
 

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