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Top Forums Shell Programming and Scripting Trouble calculating difference in number of days Post 302930283 by achenle on Thursday 1st of January 2015 01:40:35 PM
Old 01-01-2015
Way too many steps. What shell are you using?

Example in bash:

Code:
#!/bin/bash
#get some random filename just as an example
filename=/usr
mod_time=`stat -c %Y $filename`
curr_time=`date +%s`
diff_in_sec=$(( $curr_time - $mod_time ))
diff_in_days=$(( $diff_in_sec / 86400 ))
echo Diff in days:  $diff_in_days

And I wonder how reliable the use of a time difference greater then 15 full days is in determining "previous month" given that months range from 28 to 31 days long.
 

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DATEINTERVAL(3) 							 1							   DATEINTERVAL(3)

The DateInterval class

INTRODUCTION
Represents a date interval. A date interval stores either a fixed amount of time (in years, months, days, hours etc) or a relative time string in the format that DateTime's constructor supports. CLASS SYNOPSIS
DateInterval DateInterval Properties o public integer$y o public integer$m o public integer$d o public integer$h o public integer$i o public integer$s o public integer$invert o public mixed$days Methods o public DateInterval::__construct (string $interval_spec) o publicstatic DateInterval DateInterval::createFromDateString (string $time) o public string DateInterval::format (string $format) PROPERTIES
o $y - Number of years. o $m - Number of months. o $d - Number of days. o $h - Number of hours. o $i - Number of minutes. o $s - Number of seconds. o $invert - Is 1 if the interval represents a negative time period and 0 otherwise. See DateInterval::format. o $days - If the DateInterval object was created by DateTime.diff(3), then this is the total number of days between the start and end dates. Otherwise, $days will be FALSE. Before PHP 5.4.20/5.5.4 instead of FALSE you will receive -99999 upon accessing the prop- erty. PHP Documentation Group DATEINTERVAL(3)
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