Sponsored Content
Top Forums Programming Results Of A Variable Into An Array Using C Language Post 302929350 by jim mcnamara on Friday 19th of December 2014 04:53:06 PM
Old 12-19-2014
Corona corrected your problems. Consider a more generalized approach.
This is not production code. It could use more error checking, for example. I use it for quick and dirty stuff.

It breaks a file into an array of lines based on the \n character.
You could have it break on spaces or punctuation or whatever, in order to emulate creating an array of words in a file. Just change the delimiter in the split call. For large files create a larger result[] array.

You could call split again on a line and split the line by spaces + punctuation to get a word count, for example. You could add a regex call and split on just about anything.


Code:
#include "min.h"

#define AVG_LINE_SZ 20

// from M Rochkind
ssize_t readall(int fd, char *buf, size_t bytes)
 {
     ssize_t bytes_read = 0;
     ssize_t n=0;
     do {
         if ((n = read(fd,
                       &buf[bytes_read],
                       bytes - bytes_read)) == -1)
         {
             if (errno == EINTR)  // resume on INTR
             {
                 continue;
             }
             else
             {              
                 return -1;
             }
         }
         if (n == 0)
             return bytes_read;
         bytes_read += n;
     } while (bytes_read < bytes);
     return bytes_read;
 }

char **split(char **r, char *src, const char *delim)
{
   int i=0;
   char *p=strtok(src, delim);
   for( ; p; p=strtok(NULL, delim) )
   {
      r[i++]=p;
      r[i]=NULL;
   }
   return r;
}

size_t filesize(const char *fname)
{
         struct stat st;
         if(stat(fname, &st)== -1 )
         {
            fprintf(stderr, "cannot stat: %s %s\n", fname, strerror(errno));
            exit(1);
         }
         return st.st_size;
}

char *readfile(char *buf, char *fname, size_t len, char **result)
{
   FILE *fp=fopen(fname, "r");
   if(readall(fileno(fp), buf, len)>0)
   {
     split(result, buf, "\n");  // split on newlines     
     fclose(fp);
   }
   else
   {    
     perror("");
     exit(1);
   }
   return buf;

}

int main(int argc, char **argv)
{
   size_t len=(argc>1)? filesize(argv[1]): 0;
   char *result[8192]={NULL};  // <- this a problem for larger files
   int i=0;
   char *buf=(len>0)? malloc(len+2): NULL;
   if(buf==NULL) {perror(""); exit(1);}
   readfile(buf, argv[1], len, result);
   while(result[i])
     printf("%s\n", result[i++]);
   free(buf);
   return 0;  
}

This User Gave Thanks to jim mcnamara For This Post:
 

10 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

store awk results in a variable

I try to get the month (of last save) and the filename into a variable, is this possible ? something like this : for month in `ls -la | awk '{print $6}'` do if ] then a=filename of the matching file cp $a /Sep fi thanks, Steffen (1 Reply)
Discussion started by: forever_49ers
1 Replies

2. UNIX for Dummies Questions & Answers

Setting the Results of a Command to a Variable

Hi, Hi, I run the command: hostname to get the host back from the server: db201 Now, I need to take that result and set it to a variable. Can anyone help me with this?? I need to be able to use the same script on multiple servers so I do not want to hardcode the hostname result into... (1 Reply)
Discussion started by: stky13
1 Replies

3. Shell Programming and Scripting

Results of command execution into array

Hi Can anybody tell me how can I dump the results of execution of a command into array form? For example, I want to execute: and put each part of the result in an array element: Thanks (2 Replies)
Discussion started by: alirezan
2 Replies

4. Shell Programming and Scripting

Compare Array results

Hi, In a kshell , i need to compare the results of two array . each Non-match value should copy to a new array. For example: ========== Array one contain the following values: A B C Array two contain the following values: C F A E After comparing this arrays , a new array should... (4 Replies)
Discussion started by: yoavbe
4 Replies

5. UNIX for Dummies Questions & Answers

how to - redirect query results to a variable

How can I send the results of a query to a unix variable. I basically want to run a query then do some logic on the results. Trying to redirect the result into a variable I define in the script. select count(*) as counter from table - nut to redirect the "count" returned from the query... (2 Replies)
Discussion started by: rstone
2 Replies

6. Shell Programming and Scripting

Adding results of a find to an array

I'm trying to add the paths of all the xml files in certain directories to an array. I want to use the array later in my code. Anyway, for some reason this isn't working. Any help would be appreciated. Path_Counter=0 for result in "find * -name '*.xml'"; do XmlPath="$result" echo... (2 Replies)
Discussion started by: Fly_Moe
2 Replies

7. Shell Programming and Scripting

Adding grep'd results in a variable

Here is one I am baffled with; I have not used unix for a while and now that I am back it has been fun remembering and I have enjoyed it, for the most past. this is in ksh. I need to search in a file for the line with X1 and cut columns 20-25, put them into a variable, added them (dollar... (3 Replies)
Discussion started by: CougarMutt
3 Replies

8. Shell Programming and Scripting

Storing the SQL results in array variables

Requirement 1) I need to execute 15 SQL queries in oracle through linux script. All these query results needs to be stored in array variables. Requirement 2) And these 15 queries needs to be executed in parallel. Requirement 3) Once all the queries executed then the shell script should... (3 Replies)
Discussion started by: Niranjancse
3 Replies

9. Shell Programming and Scripting

Append awk results into file or array

for a in {1..100} do awk '{ sum+=$a} END {print sum}' a=$a file1 > file2 done I know I will get only one number if following the code above, how can I get 100 sum numbers in file2? (2 Replies)
Discussion started by: wanliushao
2 Replies

10. Shell Programming and Scripting

I want to add a variable for the results from the formula of one variable and results of another var

Good morning all, This is the file name in question OD_Orders_2019-02-19.csv I am trying to create a bash script to read into files with yesterdays date on the file name while retaining the rest of the files name. I would like for $y to equal, the name of the file with a formula output with... (2 Replies)
Discussion started by: Ibrahim A
2 Replies
PARSE_TIME(3)						   BSD Library Functions Manual 					     PARSE_TIME(3)

NAME
parse_time, print_time_table, unparse_time, unparse_time_approx, -- parse and unparse time intervals LIBRARY
The roken library (libroken, -lroken) SYNOPSIS
#include <parse_time.h> int parse_time(const char *timespec, const char *def_unit); void print_time_table(FILE *f); size_t unparse_time(int seconds, char *buf, size_t len); size_t unparse_time_approx(int seconds, char *buf, size_t len); DESCRIPTION
The parse_time() function converts a the period of time specified in into a number of seconds. The timespec can be any number of <number unit> pairs separated by comma and whitespace. The number can be negative. Number without explicit units are taken as being def_unit. The unparse_time() and unparse_time_approx() does the opposite of parse_time(), that is they take a number of seconds and express that as human readable string. unparse_time produces an exact time, while unparse_time_approx restricts the result to only include one units. print_time_table() prints a descriptive list of available units on the passed file descriptor. The possible units include: second, s minute, m hour, h day week seven days month 30 days year 365 days Units names can be arbitrarily abbreviated (as long as they are unique). RETURN VALUES
parse_time() returns the number of seconds that represents the expression in timespec or -1 on error. unparse_time() and unparse_time_approx() return the number of characters written to buf. if the return value is greater than or equal to the len argument, the string was too short and some of the printed characters were discarded. EXAMPLES
#include <stdio.h> #include <parse_time.h> int main(int argc, char **argv) { int i; int result; char buf[128]; print_time_table(stdout); for (i = 1; i < argc; i++) { result = parse_time(argv[i], "second"); if(result == -1) { fprintf(stderr, "%s: parse error ", argv[i]); continue; } printf("-- "); printf("parse_time = %d ", result); unparse_time(result, buf, sizeof(buf)); printf("unparse_time = %s ", buf); unparse_time_approx(result, buf, sizeof(buf)); printf("unparse_time_approx = %s ", buf); } return 0; } $ ./a.out "1 minute 30 seconds" "90 s" "1 y -1 s" 1 year = 365 days 1 month = 30 days 1 week = 7 days 1 day = 24 hours 1 hour = 60 minutes 1 minute = 60 seconds 1 second -- parse_time = 90 unparse_time = 1 minute 30 seconds unparse_time_approx = 1 minute -- parse_time = 90 unparse_time = 1 minute 30 seconds unparse_time_approx = 1 minute -- parse_time = 31535999 unparse_time = 12 months 4 days 23 hours 59 minutes 59 seconds unparse_time_approx = 12 months BUGS
Since parse_time() returns -1 on error there is no way to parse "minus one second". Currently "s" at the end of units is ignored. This is a hack for English plural forms. If these functions are ever localised, this scheme will have to change. HEIMDAL
October 31, 2004 HEIMDAL
All times are GMT -4. The time now is 04:16 AM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy