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Top Forums Programming Results Of A Variable Into An Array Using C Language Post 302929343 by metallica1973 on Friday 19th of December 2014 03:38:10 PM
Old 12-19-2014
Results Of A Variable Into An Array Using C Language

Can C add its results into an array like bash? For example using bash:
Code:
cat /etc/passwd
**truncated for space **
gdm:x:109:118:Gnome Display Manager:/var/lib/gdm:/bin/false
mysql:x:110:122:MySQL Server,,,:/nonexistent:/bin/false
statd:x:111:65534::/var/lib/nfs:/bin/false
bigbadwolf:x:1001:1001::/home/bigbadwolf:

contents of array.sh
#!/bin/bash
declare -a filecontent=(`cat "/etc/passwd"`)
echo ${filecontent[3]}|gawk -F ':' '{print $1}'
sudo ./array.sh
bigbadwolf

I began diving into the most basic of C:
Code:
cat /etc/passwd
**truncated for space **
gdm:x:109:118:Gnome Display Manager:/var/lib/gdm:/bin/false
mysql:x:110:122:MySQL Server,,,:/nonexistent:/bin/false
statd:x:111:65534::/var/lib/nfs:/bin/false
bigbadwolf:x:1001:1001::/home/bigbadwolf:

and in my adventure in doing so , I came up with this primitive little program:
Code:
    #include <stdio.h>
    #include "saint.h"
    #include "error.h"
    #include "string.h"
    #define BUFLEN 256
    char buffer[BUFLEN];
    int main() {
    FILE *fp;
    char *results;
                fp = fopen("/etc/passwd", "r");
                while(fgets(buffer, BUFLEN, fp)) {
                        if (results=strstr(buffer, "bigbadwolf" )) {
                           printf("Here are the goodies:\n%s", results);
                                        }
                        }
                fclose(fp);
        }

which simply works by passing the results of strstr --> results:
Code:
bigbadwolf:x:1001:1001::/home/bigbadwolf:

I tried to get fancy thinking that it could be easily done via attempting to declare variable and array in a one-liner but to no avail:
Code:
    #include <stdio.h>
    #include "saint.h"
    #include "error.h"
    #include "string.h"
    #define BUFLEN 256
    char buffer[BUFLEN];
    int main() {
    FILE *fp;
    //char *results[];
    //char arr[15];
    //char results;
    //results = &arr;
                fp = fopen("/etc/passwd", "r");
                while(fgets(buffer, BUFLEN, fp)) {
                        if (char *results[]=strstr(buffer, "bigbadwolf" )) {
                          printf("Here are the goodies:\n%s", results[0]);
                                        }
                        }
                fclose(fp);
        }

Code:
sudo gcc read2.c -o read
read2.c: In function ‘main':
read2.c:15:8: error: expected expression before ‘char'
    if (char *results[]=strstr(buffer, "bigbadwolf" )) {
        ^
read2.c:16:43: error: ‘results' undeclared (first use in this function)
       printf("Here are the goodies:\n%s", results[0]); 
                                           ^
read2.c:16:43: note: each undeclared identifier is reported only once for each function it appears in

How do I get bigbadwolf by itself in stdout?
Code:
bigbadwolf

Take me to the promised land please.
 

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