My task is, to write a "one-line" command, which must use ls and awk.
Task: Write a command-line, which should rename all files in dir from form "value1.dok" to "value2.doc". And value2=value1+1.
For example:
Code:
ls | awk -F: '{print "mv "$0" "$1+1".doc"}' | sh
But this doesn't work with a filename with characters. Therefore i tested this:
Code:
ls | awk -F: '{print "mv "$0" value"substr($1 ,6)+1".doc"}' | sh
This worked, but my taskprogram say "wrong" and want see a other command (perhaps with different string?)
So i tested it with regular expressions, but my console say always "syntax error":
Code:
ls | awk -F: '{print "mv "$0" "${1%[!0-9]*}""${1%[0-9]*}+1".doc"}' | sh
I havent any idea how i could it bring to work in one line...
Can someone perhaps help me?
And sorry for my very bad english
Is it possible to combine a regular expression with a aritmetical expression? For example, taking a 8-numbers caracter sequece and casting each output of a grep, comparing to a constant.
THX! (2 Replies)
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I currently list and sort all the files in a directory which begin with an Upper Case C and end with the extension '#finished#'.
Here is the command I use:
ls -tr $currentDir/*.#finished#
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CA_RELEASE has a value of 6. I need to check if that this is a numeric value. if not error.
source $CA_VERSION_DATA
if * ]
then
echo "CA_RELESE $CA_RELEASE is invalid"
exit -1
fi
+ source /etc/ncgl/ca_version_data
++ CA_PRODUCT_ID=samxts
++ CA_RELEASE=6
++ CA_WEEK_NO=7
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Hi all,
How am I read a file, find the match regular expression and overwrite to the same files.
open DESTINATION_FILE, "<tmptravl.dat" or die "tmptravl.dat";
open NEW_DESTINATION_FILE, ">new_tmptravl.dat" or die "new_tmptravl.dat";
while (<DESTINATION_FILE>)
{
# print... (1 Reply)
Hello All,
I'm trying to extract the lines between two consecutive elements of an array from a file.
My array looks like:
problem_arr=(PRS111 PRS213 PRS234)
j=0
while } ]
do
k=`expr $j + 1`
sed -n "/${problem_arr}/,/${problem_arr}/p" problemid.txt
---some operation goes... (11 Replies)
Hi,
I am quite knew to scripting and I am trying to get a regular expression to work to check that a user enters a valid version number such as 1 or 1.1 or 12.3 etc. I dont seem to be able to get it to work as it picks up versions such as 1.......2. I only want it to work with a single dot.... (12 Replies)
I would like to extract "JDBC Thin Client" from (PROGRAM=JDBC Thin Client); and "C:\Python26\python.exe" from (PROGRAM=C:\Python26\python.exe); "txm_v_awsrf_db.pr" from (PROGRAM=txm_v_awsrf_db.pr).
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Would you help suggest a regular... (4 Replies)
Discussion started by: cstsang
4 Replies
LEARN ABOUT DEBIAN
devel::refcount
Devel::Refcount(3pm) User Contributed Perl Documentation Devel::Refcount(3pm)NAME
"Devel::Refcount" - obtain the REFCNT value of a referent
SYNOPSIS
use Devel::Refcount qw( refcount );
my $anon = [];
print "Anon ARRAY $anon has " . refcount($anon) . " reference
";
my $otherref = $anon;
print "Anon ARRAY $anon now has " . refcount($anon) . " references
";
DESCRIPTION
This module provides a single function which obtains the reference count of the object being pointed to by the passed reference value.
FUNCTIONS
$count = refcount($ref)
Returns the reference count of the object being pointed to by $ref.
COMPARISON WITH SvREFCNT
This function differs from "Devel::Peek::SvREFCNT" in that SvREFCNT() gives the reference count of the SV object itself that it is passed,
whereas refcount() gives the count of the object being pointed to. This allows it to give the count of any referent (i.e. ARRAY, HASH,
CODE, GLOB and Regexp types) as well.
Consider the following example program:
use Devel::Peek qw( SvREFCNT );
use Devel::Refcount qw( refcount );
sub printcount
{
my $name = shift;
printf "%30s has SvREFCNT=%d, refcount=%d
",
$name, SvREFCNT($_[0]), refcount($_[0]);
}
my $var = [];
printcount 'Initially, $var', $var;
my $othervar = $var;
printcount 'Before CODE ref, $var', $var;
printcount '$othervar', $othervar;
my $code = sub { undef $var };
printcount 'After CODE ref, $var', $var;
printcount '$othervar', $othervar;
This produces the output
Initially, $var has SvREFCNT=1, refcount=1
Before CODE ref, $var has SvREFCNT=1, refcount=2
$othervar has SvREFCNT=1, refcount=2
After CODE ref, $var has SvREFCNT=2, refcount=2
$othervar has SvREFCNT=1, refcount=2
Here, we see that SvREFCNT() counts the number of references to the SV object passed in as the scalar value - the $var or $othervar
respectively, whereas refcount() counts the number of reference values that point to the referent object - the anonymous ARRAY in this
case.
Before the CODE reference is constructed, both $var and $othervar have SvREFCNT() of 1, as they exist only in the current lexical pad. The
anonymous ARRAY has a refcount() of 2, because both $var and $othervar store a reference to it.
After the CODE reference is constructed, the $var variable now has an SvREFCNT() of 2, because it also appears in the lexical pad for the
new anonymous CODE block.
PURE-PERL FALLBACK
An XS implementation of this function is provided, and is used by default. If the XS library cannot be loaded, a fallback implementation in
pure perl using the "B" module is used instead. This will behave identically, but is much slower.
Rate pp xs
pp 225985/s -- -66%
xs 669570/s 196% --
SEE ALSO
o Test::Refcount - assert reference counts on objects
AUTHOR
Paul Evans <leonerd@leonerd.org.uk>
perl v5.14.2 2011-11-15 Devel::Refcount(3pm)
12-07-2014
