Daniel,
is it the output of the find command? I ask this because the biggest file is ~10MB.
You mentioned UNIX 6.1, did you mean AIX 6.1? If so, then try:
Code:
find /opt -type f -size +100000000c -exec ls -l {} \;
Quote:
Would it be possible to convert the size into MB and then sort them by descending order of the file size?
Yes, the above find command should print files greater than 100000000 bytes (~100MB). Then extend the find command like so
Code:
find /opt -type f -size +100000000c -exec ls -l {} \; | sort -nrk5,5 | awk '{$5=$5/1024/1024}1'
Sample output (before sort & awk):
Code:
-rw-r----- 1 oracle dba 104865792 Jan 1 00:00 ./example01.dbf
-rw-r----- 1 oracle dba 513810432 Jan 1 00:00 ./system01.dbf
-rw-r----- 1 oracle dba 272637952 Jan 1 00:00 ./sysaux01.dbf
Sample output (after sort & awk):
Code:
-rw-r----- 1 oracle dba 490.008 Jan 1 00:00 ./system01.dbf # 490 MB
-rw-r----- 1 oracle dba 260.008 Jan 1 00:00 ./sysaux01.dbf # 260 MB
-rw-r----- 1 oracle dba 100.008 Jan 1 00:00 ./example01.dbf # 100 MB
Hope this helps.
