Please use CODE tags for code, files, input and output/errors
It makes it much easier to read and multiple spaces are respected which can be important for formatting or fixed-width input
And to get the output in the same format as the output from ls -la, try:
or, if you only want regular files to be included in the output:
hello
i need a way to list files modified in a specific month and move them to a specific directry , i mean somthing like :
find . -modifiedtime "May" -print -exec /usr/bin/mv newdirectory
thank u (1 Reply)
hello
i need a way to list files modified in a specific month and move them to a specific directry , i mean somthing like :
find . -modifiedtime "May" -print -exec /usr/bin/mv newdirectory
thank u (1 Reply)
hello
i need a way to list files modified in a specific month and move them to a specific directry , i mean somthing like :
find . -modifiedtime "May" -print -exec /usr/bin/mv newdirectory
thank u (1 Reply)
Hi All,
I am using the below command to check the files modified within last 24hours
find /home/karthik -mtime -1 -type f -exec ls -l {} \;
What parameter do i need to add in the above command to check the files modified in last 2 or 3 days
Kindly let me know if any other alternative... (2 Replies)
hello all im a newbie in the linux world ..i have just started creating basic scripts in linux ..i am using rhel 5 ..the thing is i wanted to create a find script where i could find the last modified file and directory in the directory given as input by the user and storing the output in a file so... (6 Replies)
hi,
I need to find all the modified files before 60 minutes in a folder.
Is that possible to find using mtime in minutes?
Suggestions please.
Thanks for looking into it...
Geetha (8 Replies)
Hello all - I've looked and have not been able to find a "find" command that will list the last modified date of files within a specific directory and its subdirectories. If anyone knows of such a command it would be very much appreciated!
If possible, I would like to sort this output and have... (5 Replies)
trying to find a way to locate files modified in the last hour in a shell script, unfortunately the command 'find . -mmin -60' is not supported on SunOS 5.10 (works on OpenSolaris 5.11 :mad:)
Does anyone know a method of doing this in shell script on 5.10?
cheers (19 Replies)
find list of files modified for a given day ?
if i have 10 files in my directory, i have modified only 5 ... how to display only modified files ? (1 Reply)
Hello,
I have a list of files, an example below:
-rw-r--r-- 1 smf_oper esg 910773 Jul 6 12:52 am1slc02_ACS_201607061242571_20346.cdr
-rw-r--r-- 1 smf_oper esg 995838 Jul 6 12:52 am1slc01_ACS_201607061243125_19895.cdr
-rw-r--r-- 1 smf_oper esg 557235 Jul 6 12:52... (5 Replies)
Discussion started by: nms
5 Replies
LEARN ABOUT CENTOS
shell-quote
SHELL-QUOTE(1) User Contributed Perl Documentation SHELL-QUOTE(1)NAME
shell-quote - quote arguments for safe use, unmodified in a shell command
SYNOPSIS
shell-quote [switch]... arg...
DESCRIPTION
shell-quote lets you pass arbitrary strings through the shell so that they won't be changed by the shell. This lets you process commands
or files with embedded white space or shell globbing characters safely. Here are a few examples.
EXAMPLES
ssh preserving args
When running a remote command with ssh, ssh doesn't preserve the separate arguments it receives. It just joins them with spaces and
passes them to "$SHELL -c". This doesn't work as intended:
ssh host touch 'hi there' # fails
It creates 2 files, hi and there. Instead, do this:
cmd=`shell-quote touch 'hi there'`
ssh host "$cmd"
This gives you just 1 file, hi there.
process find output
It's not ordinarily possible to process an arbitrary list of files output by find with a shell script. Anything you put in $IFS to
split up the output could legitimately be in a file's name. Here's how you can do it using shell-quote:
eval set -- `find -type f -print0 | xargs -0 shell-quote --`
debug shell scripts
shell-quote is better than echo for debugging shell scripts.
debug() {
[ -z "$debug" ] || shell-quote "debug:" "$@"
}
With echo you can't tell the difference between "debug 'foo bar'" and "debug foo bar", but with shell-quote you can.
save a command for later
shell-quote can be used to build up a shell command to run later. Say you want the user to be able to give you switches for a command
you're going to run. If you don't want the switches to be re-evaluated by the shell (which is usually a good idea, else there are
things the user can't pass through), you can do something like this:
user_switches=
while [ $# != 0 ]
do
case x$1 in
x--pass-through)
[ $# -gt 1 ] || die "need an argument for $1"
user_switches="$user_switches "`shell-quote -- "$2"`
shift;;
# process other switches
esac
shift
done
# later
eval "shell-quote some-command $user_switches my args"
OPTIONS --debug
Turn debugging on.
--help
Show the usage message and die.
--version
Show the version number and exit.
AVAILABILITY
The code is licensed under the GNU GPL. Check http://www.argon.org/~roderick/ or CPAN for updated versions.
AUTHOR
Roderick Schertler <roderick@argon.org>
perl v5.16.3 2010-06-11 SHELL-QUOTE(1)