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Full Discussion: Using sed in a loop/to remove lines contained in variable from file
Top Forums Shell Programming and Scripting Using sed in a loop/to remove lines contained in variable from file Post 302927674 by Scrutinizer on Thursday 4th of December 2014 02:42:33 PM
Old 12-04-2014
That won't work, because the substitute command in sed cannot take multiple lines..

If you are using bash and your OS supports it, try something like:
Code:
grep -vFf <(echo "$VARZ") /tmp/testfile

Otherwise you could try:
Try
Code:
echo "$VARZ" | grep -vfF - /tmp/testfile

Note that partial matches will also remove the entry, so if you do not want that it will need to be further refined..
Last edited by Scrutinizer; 12-04-2014 at 03:49 PM..
 

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LEARN ABOUT LINUX

zegrep

ZGREP(1)                                                      General Commands Manual                                                     ZGREP(1)

NAME

       zgrep - search possibly compressed files for a regular expression

SYNOPSIS

       zgrep [ grep_options ] [ -e ] pattern filename...

DESCRIPTION

       Zgrep  invokes  grep  on  compressed  or  gzipped  files.   These  grep  options  will  cause  zgrep  to  terminate  with  an  error  code:
       (-[drRzZ]|--di*|--exc*|--inc*|--rec*|--nu*).  All other options specified are passed directly to grep.  If no file is specified,  then  the
       standard input is decompressed if necessary and fed to grep.  Otherwise the given files are uncompressed if necessary and fed to grep.

       If the GREP environment variable is set, zgrep uses it as the grep program to be invoked.

EXIT CODE

       2 - An option that is not supported was specified.

AUTHOR

       Charles Levert (charles@comm.polymtl.ca)

SEE ALSO

       grep(1), gzexe(1), gzip(1), zdiff(1), zforce(1), zmore(1), znew(1)

                                                                                                                                          ZGREP(1)
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