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Top Forums Shell Programming and Scripting Bash question: working with an array of previously set variable strings Post 302927263 by hungryd on Monday 1st of December 2014 06:04:46 PM
Old 12-01-2014
i appreciate the quick response!

if the range command (which i'd never heard of) is more effective at passing a list of values than the array command, why bother using the array command? it certainly seems like range is able to accomplish what array can do and then some.

the script works as i'd intended now, so to both of you, again: thank you.
 

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COMPACT(3)								 1								COMPACT(3)

compact - Create array containing variables and their values

SYNOPSIS
array compact (mixed $varname1, [mixed $...]) DESCRIPTION
Creates an array containing variables and their values. For each of these, compact(3) looks for a variable with that name in the current symbol table and adds it to the output array such that the variable name becomes the key and the contents of the variable become the value for that key. In short, it does the opposite of extract(3). Any strings that are not set will simply be skipped. PARAMETERS
o $varname1 -compact(3) takes a variable number of parameters. Each parameter can be either a string containing the name of the variable, or an array of variable names. The array can contain other arrays of variable names inside it; compact(3) handles it recursively. RETURN VALUES
Returns the output array with all the variables added to it. EXAMPLES
Example #1 compact(3) example <?php $city = "San Francisco"; $state = "CA"; $event = "SIGGRAPH"; $location_vars = array("city", "state"); $result = compact("event", "nothing_here", $location_vars); print_r($result); ?> The above example will output: Array ( [event] => SIGGRAPH [city] => San Francisco [state] => CA ) NOTES
Note Gotcha Because variable variables may not be used with PHP's Superglobal arrays within functions, the Superglobal arrays may not be passed into compact(3). SEE ALSO
extract(3). PHP Documentation Group COMPACT(3)
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