I have thought about how to approach how to write this program but did not knowing how the log system work. There fore, I ask some questions here may offend the integrity of the forum.
First I thought if I knew how to manipulate the date string then I can control the log count of every 14 days. So I wonder how to grep things and strip things off. I had problem with bracket attach to date format such as
From the last lecture we have learned using Tr command I found it is useful to apply on how to remove the bracket.
I realized the easiest way to get the total requests of every 14 days
is find the line number of every break point of 14 days…… 0, 14, 24, 42 etc.
Pseudo:
Find the last line of the most current time in log file
Find the line number of request 14 days ago ("+%d/%b/%Y:%H:%M")
Then subtract the different to get the total number request of 14 days ago.
What I'm trying to do is perform a copy, well a ditto actually, on the results of a find command, but some inline string substitution needs to happen.
So if I run this code find ./ -name "*.tif" I get back these results.
.//1234567.tif
.//abcdefg.tif
Now the action from exec or xargs I... (2 Replies)
I'm trying to get a case statement to start over if an undefined option is selected... But I am ata loss on how to actually do it.
Here is a quick example of what I have.
Echo "1) do this/n
2) Do that/n
3) Quit/n
Make a selection/n"
Read answer
Case answer in
1) Dothid;;
2) Dothat;;... (3 Replies)
1. The problem statement, all variables and given/known data:
I have standard web server log file. It contains different columns (like IP address, request result code, request type etc) including a date column with the format .
I have developed a log analysis command line utility that displays... (1 Reply)
In a shell script, I need to grab the first or second line after a search string in a file. For example:
File.out:
Random Info
Manufacturer: XYZPDQ
System Info
Manufacturer: Hewlett-Packard
Product Name: ProLiant
I search for the word FILE, I want to be able to grab the line... (1 Reply)
Hello Unix gurus,
I have a gzipped file where each line contains 2 street addresses in the US. What I want to do is get a count for each state that does not match.
What I have so far is:
$ gzcat matched_10_09.txt.gz |cut -c 106-107,184-185 | head -5
CTCT
CTNY
CTCT
CTFL
CTMA
This cuts... (5 Replies)
I have a file like this
2011-10-10 10:46:00,1-1-13-1-1,151510,ALCLA0A84D2C
2011-10-10 10:46:00,1-1-13-1-1,151520,65537
2011-10-10 10:46:00,1-1-13-1-1,151515,46932
2011-10-10 10:46:00,1-1-13-1-1,151521,32769
2011-10-10 10:46:00,1-1-13-1-1,151522,32769
2011-10-10... (4 Replies)
Hello there! I'm having a lot of trouble writing a script.
The script is supposed to:
1) Find all files with the name "Object.mtl" within each folder in the directory: /Users/username/Desktop/convert/Objects
2) Search and replace the string ".bmp" with ".tif" (without the quotations)
3)... (1 Reply)
Use and complete the template provided. The entire template must be completed. If you don't, your post may be deleted!
1. How can i use loop to repeat task.
2.shirt=15
black=13.50
echo "how many shirt you want"
read num
echo
echo "Please enter a choice"
echo "1 ---> normal... (5 Replies)
Hi all,
I'm struggling with this task and have done alot of googling but not found the solution or atleast not found a way to combine them, i'm hoping someone here can help me out.
I have a file that contains many line of config "below is two lines for an example"
323 => 1111,Terry berry... (3 Replies)
In the file below I am trying to count the given repeats of A,T,C,G in each string of letters. Each sequence is below the > and it is possible for a string of repeats to wrap from the line above. For example, in the first line the last letter is a T and the next lines has 3 more. I think the below... (10 Replies)
Discussion started by: cmccabe
10 Replies
LEARN ABOUT CENTOS
lchage
lchage(1) General Commands Manual lchage(1)NAME
lchage - Display or change user password policy
SYNOPSIS
lchage [OPTION]... user
DESCRIPTION
Displays or allows changing password policy of user.
OPTIONS -d, --date=days
Set the date of last password change to days after Jan 1 1970.
Set days to -1 to disable password expiration (i.e. to ignore --mindays, and --maxdays and related settings).
Set days to 0 to enforce password change on next login. (This also disables password expiration until the password is changed.)
-E, --expire=days
Set the account expiration date to days after Jan 1 1970. Set days to -1 to disable account expiration.
-i, --interactive
Ask all questions when connecting to the user database, even if default answers are set up in libuser configuration.
-I, --inactive=days
Disable the account after days after password expires (after the user is required to change the password). Set days to -1 to keep
the account enabled indefinitely after password expiration.
-l, --list
Only list current user's policy and make no changes.
-m, --mindays=days
Require at least days days between password changes. Set days to 0 or -1 to disable this requirement.
If this value is larger than the value set by --maxdays, the user cannot change the pasword.
-M, --maxdays=days
Require changing the password after days since last password change. Set days to -1 to disable password expiration.
-W, --warndays=days
Start warning the user days before password expires (before the user is required to change the password). Set days to 0 or -1 to
disable the warning.
EXIT STATUS
The exit status is 0 on success, nonzero on error.
NOTES
Note that "account expiration" (set by --expire) is distinct from "password expiration" (set by --maxdays). Account expiration happens on
a fixed date regardless of password changes. Password expiration is relative to the date of last password change.
libuser Nov 8 2012 lchage(1)