A nested query must have an alias, so I added 'X' as the alias in your code:
Code:
select id, 'today', 'monthago', today, monthago
from (
SELECT id, stdate, DATE_SUB(CURDATE(), INTERVAL 1 month) as monthago, CURDATE() as today
FROM data_table X)
As regards your earlier question, in MySQL and other databases too, there is a difference between single quote (') and backquote (`). I think you meant to use the latter, which is what Ditto was getting at.
I'm an Oracle guy, not very familiar with MYSQL .. I was thinking his issue was the fact that:
where column = 'today'
is not the same as:
where column = today
if today is some internal function, then you probably shouldn't use single quotes ... if MYSQL uses back quotes ` .. then yeah, sure but I was making an assumption MYSQL treats single or double quotes as strings.
which would be like trying to match:
where Nov 25, 2014 = "today" ..
as opposed to:
where Nov 25, 2014 = Nov 25, 2014
(ie where date_col = today ) ??
Hi there,
I have a hierarchical database that include 4 tables. Table A is the parent of B, B is Parent of C, C is parent of D. If I want to query everything in D that is associated with A.name, how do I do that? Thanks!
YanYan (0 Replies)
hello all
i have 2 columns every column in the following format
column1
2011-04-01 11:39:54
column2
2019-02-03 00:00:00
i want get difference between above data as following
2 days 11:39
how to do so ?
i tried many functions but nothing works
please advice what is the query... (6 Replies)
Hi,
I want to run below query on shellscript but having one problm.
ADV=$( mysql -h "$IP_ADDR" -u "$USER_NAME" "$TABLE_NAME" -BNe" SELECT ADV FROM indata where inid='$INSTRUID' and Date='$latest Date';" )
here Date column contans different below dates
2011-12-01... (11 Replies)
Hello
i have created mysql query to compare to values and get difference in percentage
as following:
SELECT file_name, 100 - ((100 * (SELECT file_count FROM xipi_files z WHERE x.file_group = z.file_group AND x.file_name = z.file_name AND z.insert_date = CURDATE( ) - INTERVAL 1 DAY)) /... (1 Reply)
Hi,
I've written a script to search for an Oracle ORA- error on a log file, print that line and the .trc file associated with it as well as the dateline of when I assumed the error occured. In most it is the first dateline previous to the error.
Unfortunately, this is not a fool proof script.... (2 Replies)
Hi All,
i have a table in mysql with the following data
Table name Test
Assettype Serial_No Status location
Mouse 123456 In Stock chennai
Mouse 98765 Allocated chennai
Keyboard ... (2 Replies)
Discussion started by: venkitesh
2 Replies
LEARN ABOUT PHP
cal_from_jd
CAL_FROM_JD(3) 1 CAL_FROM_JD(3)cal_from_jd - Converts from Julian Day Count to a supported calendarSYNOPSIS
array cal_from_jd (int $jd, int $calendar)
DESCRIPTION cal_from_jd(3) converts the Julian day given in $jd into a date of the specified $calendar. Supported $calendar values are CAL_GREGORIAN,
CAL_JULIAN, CAL_JEWISH and CAL_FRENCH.
PARAMETERS
o $jd
- Julian day as integer
o $calendar
- Calendar to convert to
RETURN VALUES
Returns an array containing calendar information like month, day, year, day of week, abbreviated and full names of weekday and month and
the date in string form "month/day/year".
EXAMPLES
Example #1
cal_from_jd(3) example
<?php
$today = unixtojd(mktime(0, 0, 0, 8, 16, 2003));
print_r(cal_from_jd($today, CAL_GREGORIAN));
?>
The above example will output:
Array
(
[date] => 8/16/2003
[month] => 8
[day] => 16
[year] => 2003
[dow] => 6
[abbrevdayname] => Sat
[dayname] => Saturday
[abbrevmonth] => Aug
[monthname] => August
)
SEE ALSO cal_to_jd(3), jdtofrench(3), jdtogregorian(3), jdtojewish(3), jdtojulian(3), jdtounix(3).
PHP Documentation Group CAL_FROM_JD(3)
11-25-2014
I was thinking his issue was the fact that: