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Full Discussion: How to extract start/end times from log file to CSV file?
Top Forums Shell Programming and Scripting How to extract start/end times from log file to CSV file? Post 302926335 by derekludwig on Sunday 23rd of November 2014 01:08:35 PM
Old 11-23-2014
Modification of RudiC script (I unrolled the pipeline just to make it clearer to myself) that doesn't use the %(datefmt)T format of printf
Code:
awk '{print $3"-"$2"-"$1" "$4":"$5}' FS="[-: ]" "${1}" \
| date -f- +%s \
| {
  read oldT
  echo -n "${oldT} "
  N=1
  while read curT; do
    if [[ $(( curT - oldT )) -gt 60 ]]; then
      echo ${oldT} ${N}
      echo -n "${curT} "
      N=0
    fi
    oldT=${curT}
    (( N++ ))
  done
  echo ${oldT} ${N}
} \
| while read oldT newT N; do
  echo $(date +%d-%m-%Y\ %H:%M -d @${oldT}),$(date +%d-%m-%Y\ %H:%M -d @${newT}),${N}
done

See the manpage if your version of date doesn't support -d @seconds.
Testing with a larger dataset:
Code:
14-11-2014 05:23
14-11-2014 05:24
14-11-2014 05:25
14-11-2014 05:26
16-11-2014 13:01
16-11-2014 13:02
16-11-2014 13:03
23-11-2014 03:00
23-11-2014 05:24
23-11-2014 05:25
24-11-2014 08:24
24-11-2014 08:25
25-11-2014 08:58
25-11-2014 08:59
25-11-2014 09:00
25-11-2014 09:01
31-12-2014 23:47
31-12-2014 23:48
31-12-2014 23:49
    snip
01-01-2015 00:05
01-01-2015 00:06
01-01-2015 00:07

yielded:
Code:
14-11-2014 05:23,14-11-2014 05:26,4
16-11-2014 13:01,16-11-2014 13:03,3
23-11-2014 03:00,23-11-2014 03:00,1
23-11-2014 05:24,23-11-2014 05:25,2
24-11-2014 08:24,24-11-2014 08:25,2
25-11-2014 08:58,25-11-2014 09:01,4
31-12-2014 23:47,01-01-2015 00:07,21

(thanks to RudiC for giving me a starting point)
These 2 Users Gave Thanks to derekludwig For This Post:
Mr.Zizo RudiC
 

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