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Top Forums Shell Programming and Scripting Split File based on number of rows Post 302925716 by kpk_ds on Wednesday 19th of November 2014 12:08:57 AM
Old 11-19-2014
Split File based on number of rows

Hi

I have a requirement, where i will receive multiple files in a folder (say: /fol1/fol2/). There will be at least 14 to 16 files. The size of the files will different, some may be 80GB or 90GB, some may be less than 5 GB (and the size of the files are very unpredictable). But the names of the files will be have a particular format like "Table1_Insert.dat" , Table1_Update.dat, Table1_delete.dat, Table2_ins.dat, Table2_upd.dat, Table2_del.dat... like this...

I have to read one file at a time, check the size of the file (in GB), if the file size is greater than 90 GB (file size wont be more than 100GB always), then split the files into 5GB. So if the file size is 90 GB, then it should split the source file into 18 sub files (like TT_table1_ins.dataa, TT_Table1_ins.datab , TT_Table1_ins.datac... etc)

I want my script to take only one input argument - just the file name (with the path).

I know we can do this using split -l command, but i need some help. Can somebody help me with a script. I'm very new to shell scripting. I can understand the commands but cannot write a script... Smilie

Thanks
 

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RECEIVE(1)						      General Commands Manual							RECEIVE(1)

NAME
receive - receive files from the sendfile spool SYNOPSIS
receive [ -d ] [ -r ] [ -k ] [ -P ] [ -S ] [ -Z spool ] [ -q ] [ -ffrom ] file [...] receive -n [ -d ] [ -r ] [ -k ] [ -P ] [ -S ] [ -Z spool ] [ -q ] file-number [...] receive [ -s ] [ -l ] [ -L ] [ -R ] [ -ffrom ] receive -b user[@host] [ -k ] [ -f"from" ] file [...] receive -b user[@host] [ -k ] [ -f"from" ] -n file-number [...] receive -b user[@host] [ -k ] -a DESCRIPTION
receive files from the sendfile spool which has been sent to you. If there is already a file with the same name you will be prompted for overwriting or renaming. Allowed wildcards in file names are: * ? [abc] [^abc] CAUTION: you have to put wildcards and other special characters in '' quotes to hide them for interpretation by your shell. OPTIONS
-n receive file number(s) -d delete instead of receive -a receive (or delete or bounce) all files -r rename before receiving -k keep files in spool after receiving -P pipe files to stdout -S receive only pgp-signed files -s list files in short format -l list files -L list files and look inside archives, too -R renumber files in spool -b bounce (forward) files to another recipient -q quiet mode: no questions asked -fuser all actions refer only to files from this user -Z spool specify an alternate spool directory EXAMPLES
receive -L list all files in long format. receive 'blubb*' receive all files starting with string "blubb". receive -daf microsoft.com delete all files from microsoft.com sites. receive -b framstag@bofh '*.jpg' bounce all *.jpg-files to framstag@bofh. FILES
/var/spool/sendfile The sendfile spool directory. /var/spool/sendfile/$USER/log A log of the last transfers. /etc/sendfile.deny Users which are not allowed to receive files or messages (set by root). SEE ALSO
sendfile(1). AUTHOR
Ulli Horlacher - framstag@rus.uni-stuttgart.de 3rd Berkeley Distribution RECEIVE(1)
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