I'm having problems since few days ago, and i'm not able to make it works with a simple awk+grep script (or other way to do this).
For example, i have a input file1.txt:
cat inputfile1.txt
218299910417
1172051195
1172070231
1172073514
1183135117
1183135118
1183135119
1281440202
... (3 Replies)
Hi,
I have a table to be imported for R as matrix or data.frame but I first need to edit it because I've got several lines with the same identifier (1st column), so I want to sum the each column (2nd -nth) of each identifier (1st column)
The input is for example, after sorted:
K00001 1 1 4 3... (8 Replies)
Hi All,
I have a requirement where I need to find sum of values from column D through O present in a CSV file and check whether the sum of each Individual column matches with the value present for that corresponding column present in the trailer record.
For example, let's assume for column D... (9 Replies)
file:
1|12322|tow|
5|23422|pow|
6|23423|cow|
3|34324|how|
deletelines:
12322
23423
My command to delete line
while read NUM
do
awk -F"\|" '$2 !~ /`"$NUM"`/' file >file.back
mv file.back file
done<deletelines (3 Replies)
I have a file with class c IP addresses that I need to match to a column and print the matching lines of another file.
I started playing with grep -if file01.out file02.out but I am stuck as to how to match it to a column and print the matching lines;
cat file01.out
10.150.140... (5 Replies)
Hi,
I have some data like below:
John 254
Chris 254
Matt 123
Abe 123
Raj 487
Moh 487
How can i print it using awk to have:
254 John,Chris
123 Matt,Abe
487 Raj,Moh
Thanks. (4 Replies)
Hi Experts,
Please bear with me, i need help
I am learning AWk and stuck up in one issue.
First point : I want to sum up column value for column 7, 9, 11,13 and column15 if rows in column 5 are duplicates.No action to be taken for rows where value in column 5 is unique.
Second point : For... (1 Reply)
hi
I have 2 file with more than 10 columns for both
1st file
apple,0,0,0......
orange,1,2,3.....
mango,2,4,5.....
2nd file
apple,2,3,4,5,6,7...
orange,2,3,4,5,6,8...
watermerlon,2,3,4,5,6,abc...
mango,5,6,7,4,6,def.... (1 Reply)
Discussion started by: tententen
1 Replies
LEARN ABOUT DEBIAN
bup-margin
bup-margin(1) General Commands Manual bup-margin(1)NAME
bup-margin - figure out your deduplication safety margin
SYNOPSIS
bup margin [options...]
DESCRIPTION
bup margin iterates through all objects in your bup repository, calculating the largest number of prefix bits shared between any two
entries. This number, n, identifies the longest subset of SHA-1 you could use and still encounter a collision between your object ids.
For example, one system that was tested had a collection of 11 million objects (70 GB), and bup margin returned 45. That means a 46-bit
hash would be sufficient to avoid all collisions among that set of objects; each object in that repository could be uniquely identified by
its first 46 bits.
The number of bits needed seems to increase by about 1 or 2 for every doubling of the number of objects. Since SHA-1 hashes have 160 bits,
that leaves 115 bits of margin. Of course, because SHA-1 hashes are essentially random, it's theoretically possible to use many more bits
with far fewer objects.
If you're paranoid about the possibility of SHA-1 collisions, you can monitor your repository by running bup margin occasionally to see if
you're getting dangerously close to 160 bits.
OPTIONS --predict
Guess the offset into each index file where a particular object will appear, and report the maximum deviation of the correct answer
from the guess. This is potentially useful for tuning an interpolation search algorithm.
--ignore-midx
don't use .midx files, use only .idx files. This is only really useful when used with --predict.
EXAMPLE
$ bup margin
Reading indexes: 100.00% (1612581/1612581), done.
40
40 matching prefix bits
1.94 bits per doubling
120 bits (61.86 doublings) remaining
4.19338e+18 times larger is possible
Everyone on earth could have 625878182 data sets
like yours, all in one repository, and we would
expect 1 object collision.
$ bup margin --predict
PackIdxList: using 1 index.
Reading indexes: 100.00% (1612581/1612581), done.
915 of 1612581 (0.057%)
SEE ALSO bup-midx(1), bup-save(1)BUP
Part of the bup(1) suite.
AUTHORS
Avery Pennarun <apenwarr@gmail.com>.
Bup unknown-bup-margin(1)