11-03-2014
Snapshot revert fails in my KVM setup
Hi All,
I am trying to revert a snapshot and I am getting the below error message in my KVM setup (RHEL6.5). Reverting to a snapshot is failing.
Quote:
#virsh snapshot-revert TestImg Deployed-Stage --force
error: An error occurred, but the cause is unknown
I used the below command to create the snapshot.
Quote:
virsh snapshot-create-as TestImg Deployed-Stage --disk-only --atomic --no-metadata
Below is my snapshot list:
virsh snapshot-list TestImg –tree
Quote:
Deployed-Stage
|
+- Snapshot1
|
+- Snapshot2
Snapshot Info:
Quote:
virsh snapshot-info TestImg --snapshotname Deployed-Stage
Name: Deployed-Stage
Domain: TestImg
Current: no
State: shutoff
Location: external
Parent: -
Children: 1
Descendants: 2
Metadata: yes
Virsh version:
Quote:
virsh version
Compiled against library: libvirt 0.10.2
Using library: libvirt 0.10.2
Using API: QEMU 0.10.2
Running hypervisor: QEMU 0.12.1
libvirtd.log has below warning message
Quote:
2014-11-03 14:14:17.261+0000: 8025: warning : qemuDomainSnapshotForEachQcow2Raw:1723 : skipping snapshot action on vda
Please help me on this.
Thanks,
Kalpeer
Last edited by kalpeer; 11-03-2014 at 10:16 AM..
Reason: Update the text
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LEARN ABOUT DEBIAN
shell-quote
SHELL-QUOTE(1p) User Contributed Perl Documentation SHELL-QUOTE(1p)
NAME
shell-quote - quote arguments for safe use, unmodified in a shell command
SYNOPSIS
shell-quote [switch]... arg...
DESCRIPTION
shell-quote lets you pass arbitrary strings through the shell so that they won't be changed by the shell. This lets you process commands
or files with embedded white space or shell globbing characters safely. Here are a few examples.
EXAMPLES
ssh preserving args
When running a remote command with ssh, ssh doesn't preserve the separate arguments it receives. It just joins them with spaces and
passes them to "$SHELL -c". This doesn't work as intended:
ssh host touch 'hi there' # fails
It creates 2 files, hi and there. Instead, do this:
cmd=`shell-quote touch 'hi there'`
ssh host "$cmd"
This gives you just 1 file, hi there.
process find output
It's not ordinarily possible to process an arbitrary list of files output by find with a shell script. Anything you put in $IFS to
split up the output could legitimately be in a file's name. Here's how you can do it using shell-quote:
eval set -- `find -type f -print0 | xargs -0 shell-quote --`
debug shell scripts
shell-quote is better than echo for debugging shell scripts.
debug() {
[ -z "$debug" ] || shell-quote "debug:" "$@"
}
With echo you can't tell the difference between "debug 'foo bar'" and "debug foo bar", but with shell-quote you can.
save a command for later
shell-quote can be used to build up a shell command to run later. Say you want the user to be able to give you switches for a command
you're going to run. If you don't want the switches to be re-evaluated by the shell (which is usually a good idea, else there are
things the user can't pass through), you can do something like this:
user_switches=
while [ $# != 0 ]
do
case x$1 in
x--pass-through)
[ $# -gt 1 ] || die "need an argument for $1"
user_switches="$user_switches "`shell-quote -- "$2"`
shift;;
# process other switches
esac
shift
done
# later
eval "shell-quote some-command $user_switches my args"
OPTIONS
--debug
Turn debugging on.
--help
Show the usage message and die.
--version
Show the version number and exit.
AVAILABILITY
The code is licensed under the GNU GPL. Check http://www.argon.org/~roderick/ or CPAN for updated versions.
AUTHOR
Roderick Schertler <roderick@argon.org>
perl v5.8.4 2005-05-03 SHELL-QUOTE(1p)