10-31-2014
Thanks, folks, for the clarifications and input.
Quote:
If the shell would find the \ outside a 'string' it would quote the next character, so you would need \\\\ in your perl code -> Perl passes \\ to the shell -> the shell passes \ to sed -> sed finds \|
You should really do that in Perl...
Thanks, MadeInGermany, for the smile. I do agree; but I also truly love Monty Python
Thanks again; and have a great weekend!
10 More Discussions You Might Find Interesting
1. UNIX for Dummies Questions & Answers
is it possible to escape the \ character in sed?
right now I'm trying to replace all occurances of \ with \\
sed \"s|test|test_replacement|g\" file1 > output; #this works fine
sed \"s|\\|\\\|g\" file1 > output; #this generates the following error:
sed: -e expression #1, char 17:... (1 Reply)
Discussion started by: gammaman
1 Replies
2. Shell Programming and Scripting
I have one File named "txt_file"
# cat txt_file
<DBType>RT</DBType>
<AppType>RT</AppType>
--------------------------------------------------
I want replace "<AppType>RT</AppType>" to
<AppType>XY</AppType> in txt_file and output redirect to Newfile
... (2 Replies)
Discussion started by: SanjayLinux
2 Replies
3. Shell Programming and Scripting
I am aware that Perl has a lot of features that originally came from sed and awk. I have a pattern that I am using like this:
sed -n '/|Y|/p'
I want to do the same thing in Perl and be able to either save that value in some kind of variable or array or potentially write it out to a file.
... (11 Replies)
Discussion started by: masinick
11 Replies
4. Shell Programming and Scripting
Hi All,
How do i write in sed for the 6th and 7th field of etc/passwd file as it involves "/" character?
Does mine below is correct? It's incomplete script as i need help with syntax as i always getting may errors :(
Example of etc/passwd file:
blah:x:1055:600:blah... (6 Replies)
Discussion started by: c00kie88
6 Replies
5. Shell Programming and Scripting
Hi all,
I have a script which uses sed to replace one string with another. The problem is, the string to be matched, and its replacement are coming in as two command line arguments $1 and $2
$1 and $2 can be absolutely anything, but both should be treated purely as strings. My sed command... (7 Replies)
Discussion started by: mark007
7 Replies
6. Shell Programming and Scripting
my @array;
my $sepa = "|";
print $sepa;
open FH, "<100_20091023_2.txt";
while(<FH>){
push @array, split(/\$sepa/, $_);
print "@array\n\n";
}
I am not able split the line which have | separated (1 Reply)
Discussion started by: pritish.sas
1 Replies
7. Shell Programming and Scripting
Hi,
I am facing an issue with sed in perl. I have a file which has 2 header lines and one trailer line. I need to process the file without these headers and trailer. My file looks like :
File.txt:-
Header1
Header2
data1
data2
trailer
For removing header and trailer from file I am using... (5 Replies)
Discussion started by: abhisharma23
5 Replies
8. Shell Programming and Scripting
Hi all,
I've got a problem with sed. Want to use it to add escape character \ before $ and ' symbols so
condition='1'$some will become condition=\'1\'\$some
echo "condition='1'$some" | sed 's/\($\)/\\\1/g'
is not working properly. Can somebody help me with this please?
Regards,... (7 Replies)
Discussion started by: johny_be_good
7 Replies
9. Shell Programming and Scripting
i have string as below
str=".<date>"
in which i need to replace < with /< , when i tried with sed , got the output.
--> echo $str | sed 's/</\\</g'
.\<date>
when i tried to assign it to a variable , i am not getting the same
--> a=`echo $str | sed 's/</\\</g'` ; echo $a... (4 Replies)
Discussion started by: expert
4 Replies
10. UNIX for Beginners Questions & Answers
Hello,
I am running ubuntu 16.04
I searched "how to replace dot by % using sed" but no luck.
file
My.Name.Is.Earl
Expected output
My%Name%Is%Earl
I tried:
sed -i "s|.||g" file
sed -i "s|.|{%}|g" file
sed -i "s|.|\%|g" file
I'd appreciate your help
Thank you
Boris (6 Replies)
Discussion started by: baris35
6 Replies
LEARN ABOUT DEBIAN
lp-shell
lp-shell(1) General Commands Manual lp-shell(1)
NAME
lp-shell - Open an interactive launchpadlib shell.
SYNOPSIS
lp-shell [-a] [-cPROGRAM] [--python] [--ipython] [service] [LP API version]
DESCRIPTION
lp-shell opens an interactive Python shell with a launchpadlib.Launchpad object "lp" which is ready for use.
It authenticates against Launchpad with the consumer name "udt-lp-shell". When using lp-shell with the -a option it will use the anonymous
login from launchpadlib.Launchpad.
By default lp-shell connects to the "production" Launchpad service using the "1.0" LP API version.
If you want to connect to another Launchpad service, call lp-shell with the service name as the second argument. lp-shell supports all ser-
vices known by launchpadlib Python module. Currently known are (list can be incomplete or outdated): "production", "staging", "dogfood".
A different LP API version can be selected by passing the API version to use as the third argument. Current supported are: "beta", "1.0"
and "devel".
OPTIONS
-a Login anonymously into Launchpad.
-c PROGRAM
Don't enter a shell but only run the specified Python program and exit.
--ipython
Use an ipython shell if available (default).
--python
Use a regular python shell.
AUTHORS
lp-shell was written by Martin Pitt <martin.pitt@ubuntu.com>.
It is released under the terms of the GNU General Public License, version 2 or (at your option) any later version.
lptools 27 March 2010 lp-shell(1)