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Top Forums UNIX for Dummies Questions & Answers Passing Shell Variable to awk Post 302922102 by Ariean on Wednesday 22nd of October 2014 11:40:00 AM
Old 10-22-2014
Passing Shell Variable to awk

Hello All,

May i please why my shell variable is not getting passed into awk script.

HTML Code:
#!/bin/bash -vx

i="1EB07C50"

/bin/awk -v ID="$i" '/ID/ {match($0,/ID/);print substr($0,RSTART,RLENGTH)}' /var/log/ScriptLogs/keys.13556.txt
Thank you.
 

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IGAWK(1)							 Utility Commands							  IGAWK(1)

NAME
igawk - gawk with include files SYNOPSIS
igawk [ all gawk options ] -f program-file [ -- ] file ... igawk [ all gawk options ] [ -- ] program-text file ... DESCRIPTION
Igawk is a simple shell script that adds the ability to have ``include files'' to gawk(1). AWK programs for igawk are the same as for gawk, except that, in addition, you may have lines like @include getopt.awk in your program to include the file getopt.awk from either the current directory or one of the other directories in the search path. OPTIONS
See gawk(1) for a full description of the AWK language and the options that gawk supports. EXAMPLES
cat << EOF > test.awk @include getopt.awk BEGIN { while (getopt(ARGC, ARGV, "am:q") != -1) ... } EOF igawk -f test.awk SEE ALSO
gawk(1) Effective AWK Programming, Edition 1.0, published by the Free Software Foundation, 1995. AUTHOR
Arnold Robbins (arnold@skeeve.com). Free Software Foundation Nov 3 1999 IGAWK(1)
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