It is a function of python to return the length (the number of items) in an object.
In this case number of values.
Okay, I want to do something similar but with strings and dictionaries. If I have this file:
I want to split this up into id and name where id is the number and name is the rest of the string. Then I want to store the entries into a dictionary. I was looking at the dictionary function and was wondering how it would work. I started it but don't know how to put it into a dictionary.
This is the cronjob
----------------------
root@a7germ:/home/paxtemp > crontab -l|grep test
57 * * * * /home/paxtemp/test_1.sh
0,5,10,15,20,25,30,35,40,45,50,55 * * * * /home/paxtemp/test.sh
root@a7germ:/home/paxtemp >
This is the contents of test.sh script... (2 Replies)
Hi All
I like to know how can we calculate the number of rows and the average of the values present in the file. I will not know what will be the rowcount, which will be dynamic in nature of the file.
eg.
29
33
48
30
28 (6 Replies)
Dear all,
i have 200 values in a file. How can i calculate a weighted average and output into a new file avg.dat?
INPUT:
file1.dat
1.3453
2.434
2.345
.....
OUTPUT:
avg.dat
file1: 1.762
Thanks.
Po (3 Replies)
Hey guys.....
I have many files (lets say 100 or more) of same size, and I want to create a new output file and calculate the average of first row fifth column in all files and print it in first row of output file, then 2nd row fifth col in all 100 files and print it in 2nd row of output... (1 Reply)
Is there an awk script that can easily perform the following operation?
I have a data file that is in the format of
1944-12,5.6
1945-01,9.8
1945-02,6.7
1945-03,9.3
1945-04,5.9
1945-05,0.7
1945-06,0.0
1945-07,0.0
1945-08,0.0
1945-09,0.0
1945-10,0.2
1945-11,10.5
1945-12,22.3... (3 Replies)
Hi
I have file like below
111,victor,48,12,36
342,Peter,54,58,30
476,Scott,25,36,48
567,Patty,74,17,95
I have written below code to calcualte avereage for every id
Victor = 48+12+36/3
#!/bin/ksh
/usr/xpg4/bin/awk '
BEGIN {FS=","} {sum=0; n=0;i=3 (1 Reply)
I have some files with the following contents.I would like to calculate average of fifth column. How can I do this with awk?
file1
cat 95.9 152 78.0 17.9
rat 67.1 153 36.5 30.6
dog 81.4 154 68.1 13.3
dog 92.0 155 55.5 36.5
rat 73.8 156 23.9 49.9
file2
rat... (4 Replies)
Discussion started by: avina
4 Replies
LEARN ABOUT DEBIAN
wtoc
WTOC(1) General Commands Manual WTOC(1)NAME
wtoc - Convert a Wnn text-form dictionary (or dictionaries) into Canna text-form dictionaries
SYNOPSIS
wtoc [-f hinshidata] [wnnjisho] [cannajisho]
DESCRIPTION
wtoc converts a Wnn text-form dictionary file into Canna text-form dictionary file. If all dictionary files are omitted, the Wnn dictio-
nary data is input through the standard input. In this case, the dictionary of the Japanes Input System is output from the standard out-
put. If one dictionary file is specified, it will be regarded as a Wnn dictionary. At this time, Canna dictionary output to the standard
output.
OPTIONS -f hinshidata
The user can add new information about word-type correspondence between Wnn and Canna. The following word-type correspondence
information must be described in the hinshidata file. Within one line, describe the Wnn word type name and the Canna word type
while delimiting by a space(s) or tab.
Wnn word type Canna word type
Adverb #F04
EXAMPLE
% wtoc -f tsuikahinshi kihon.u kihon.t
Inputs word-type correspondence information from tsuikahinshi, then converts Wnn text-form dictionary kihon.u into the Canna text-form dic-
tionary before output.
% wtoc special.u | lpr
Converts Wnn text-form dictionary special.u into Canna text-form dictionary, then outputs the result to the line printer.
SEE ALSO ctow(1)WTOC(1)