10-16-2014
Depending on the shell and the user you run it under, changing the umask to 022 might be sufficient.
10 More Discussions You Might Find Interesting
1. UNIX for Dummies Questions & Answers
Hi, I'm new to unix -solaris.
I've just upgraded a third party software product and am testing
it to see if new files created in a test database directory were being created properly and they aren't. They're owned by the user that created the file, instead of poppa and the group of their files... (2 Replies)
Discussion started by: avisb
2 Replies
2. HP-UX
Hi,
I am a Unix Admin. I have to give the permissions to a user for creating new file in a directory in HP-Ux 11.11 system since he cannot able to create a new file in the directory.
Thanks in advance.
Mike (3 Replies)
Discussion started by: Mike1234
3 Replies
3. UNIX for Dummies Questions & Answers
Hi,
I've searched and read, and searched and read some more; but I'm still not connecting the dots or understanding what I need to change.
I have a script that creates a file. If I run it as root, the file gets created with 644 permissions like I want. That seems to make sense (at least I... (2 Replies)
Discussion started by: 65bit
2 Replies
4. Shell Programming and Scripting
Hi,
i have say 100 files in a directory.
file1.log
file2.log
file3.log
file4.log
file5.log
file6.log
...
...
...
file99.log
file100.log
=========
I need to create another file which contains the list of al these log files.
each file should contain only 10 log file names.
it shud... (4 Replies)
Discussion started by: robinbannis
4 Replies
5. Shell Programming and Scripting
Hi,
How do i check if I have read/write/execute rights on a UNIX directory?
What I'm doing is checking read access on the files but i also want to check if user has rights on the direcory in whcih these files are present.
if then......
And I check if the directory exists by using... (6 Replies)
Discussion started by: chetancrsp18
6 Replies
6. UNIX for Dummies Questions & Answers
I have more than 10K songs in two directories on a hard drive. I would like to create a file list all of files name then change to .xml extension to upload to iPhone so I have a Karaoke list on my iPhone.
I need your help to create a file by using command in Linux.
Files names:
0001 More... (4 Replies)
Discussion started by: ggcc
4 Replies
7. Shell Programming and Scripting
Hello
I putting together a menu script for some processing operations and I want to do the following, was googling for some time, but can figure the following out.
Im in a folder lets say /input_files
I want to list the files something like the following, each file is assigned a number,... (3 Replies)
Discussion started by: kl1ngac1k
3 Replies
8. Shell Programming and Scripting
Hi all,
i have a folder, with tons of files containing as following,
on /my/folder/jobs/
some_name_2016-01-17-22-38-58_some name_0_0.zip.done
some_name_2016-01-17-22-40-30_some name_0_0.zip.done
some_name_2016-01-17-22-48-50_some name_0_0.zip.done
and these can be lots of similar files,... (6 Replies)
Discussion started by: charli1
6 Replies
9. Shell Programming and Scripting
Hi All,
We have main directory called "head"
under this we have several sub directories and under these directories we have sub directories.
My requirement is I have to find the SQL files which are having the string "procedure" under "head" directory and sub directories as well.
And create... (14 Replies)
Discussion started by: ROCK_PLSQL
14 Replies
10. UNIX for Beginners Questions & Answers
I have an interactive script which works terrific at processing a folder of unsorted files into new directories.
I am wondering how I could modify my script so that( upon execution) it provides an additional labelled summary file on my desktop that lists all of the files in each directory that... (4 Replies)
Discussion started by: Braveheart
4 Replies
LEARN ABOUT LINUX
pam_umask
PAM_UMASK(8) Linux-PAM Manual PAM_UMASK(8)
NAME
pam_umask - PAM module to set the file mode creation mask
SYNOPSIS
pam_umask.so [debug] [silent] [usergroups] [umask=mask]
DESCRIPTION
pam_umask is a PAM module to set the file mode creation mask of the current environment. The umask affects the default permissions assigned
to newly created files.
The PAM module tries to get the umask value from the following places in the following order:
o umask= argument
o umask= entry of the users GECOS field
o pri= entry of the users GECOS field
o ulimit= entry of the users GECOS field
o UMASK= entry from /etc/default/login
o UMASK entry from /etc/login.defs
OPTIONS
debug
Print debug information.
silent
Don't print informative messages.
usergroups
If the user is not root and the username is the same as primary group name, the umask group bits are set to be the same as owner bits
(examples: 022 -> 002, 077 -> 007).
umask=mask
Sets the calling process's file mode creation mask (umask) to mask & 0777. The value is interpreted as Octal.
MODULE TYPES PROVIDED
Only the session type is provided.
RETURN VALUES
PAM_SUCCESS
The new umask was set successfully.
PAM_SERVICE_ERR
No username was given.
PAM_USER_UNKNOWN
User not known.
EXAMPLES
Add the following line to /etc/pam.d/login to set the user specific umask at login:
session optional pam_umask.so umask=0022
SEE ALSO
pam.conf(5), pam.d(5), pam(7)
AUTHOR
pam_umask was written by Thorsten Kukuk <kukuk@thkukuk.de>.
Linux-PAM Manual 06/04/2011 PAM_UMASK(8)