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Full Discussion: Getting data with unstable space
Top Forums Shell Programming and Scripting Getting data with unstable space Post 302919779 by kenshinhimura on Friday 3rd of October 2014 03:32:44 PM
Old 10-03-2014
unfortunately..i cant change the date...so i will adjust my command..

the system works likes this..

Code:
$date
Oct   3

if 10 days above
$date
Oct 11

But this works for me.. thanks guys

Code:
awk '{ printf("%s %*s\n", $2, 2, $3) }'

---------- Post updated at 02:21 PM ---------- Previous update was at 02:21 PM ----------

Quote:
Originally Posted by Franklin52
With printf you can use the width trick, something like:
Code:
date | awk '{ printf("%s %*s\n", $2, 2, $3) }'

awesome sir...

---------- Post updated at 02:23 PM ---------- Previous update was at 02:21 PM ----------

Quote:
Originally Posted by Don Cragun
The logical way to get the abbreviated month and day is to use date by itself:
Code:
date '+%b %e'

If you insist on using awk:
Code:
date | awk '{printf("%s%3d\n", $2, $3)}'

If you insist on using sed:
Code:
date | sed 's/....\(......\).*/\1/'

And, if you like cut:
Code:
date | cut -c5-10

this works as well..thanks sir...

Code:
date | awk '{printf("%s%3d\n", $2, $3)}

---------- Post updated at 02:32 PM ---------- Previous update was at 02:23 PM ----------

Don/Franklin

can you explain this? character by character?? Please???

thanks

Code:
awk '{printf("%s%3d\n", $2, $3)}'
 awk '{ printf("%s %*s\n", $2, 2, $3) }'

sed 's/....\(......\).*/\1/'

 

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