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Top Forums Shell Programming and Scripting Check daily files arrival in a directory Post 302919073 by flagboy2014 on Saturday 27th of September 2014 02:16:06 PM
Old 09-27-2014
Hi pilnet101,

Thanks for your reply.
I am just beginner in unix and wrote this code with the help of online tutorials so far for 2 files -
Code:
#!/bin/bash

echo "Enter date of file"
read date;
for x in {1}  ; 
do
    if [[ -f "new1_$date.txt" ]]; then
        echo "new1_$date.txt is a present"
    else 
        echo "BOOOOO...new1_$date.txt is absent"
fi
	if [[ -f "new2_$date.txt" ]]; then
        echo "new2_$date.txt is a present"
    else 
        echo "new2_$date.txt is absent"
    fi

if [[ -f "new3_$date.txt" ]]; then
        echo "new3_$date.txt is a present"
    else 
        echo "new3_$date.txt is absent"
    fi


done


but this isn't working for all files.

i have files like this -
Code:
howdy_20140925_XXXX.txt
hello_20140925_xxxx.txt
Fine_20140925.2599

these files come daily and i need to write script to check whether they come or not.

Thanks.

Last edited by Franklin52; 09-27-2014 at 06:24 PM.. Reason: Please use code tags
 

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DATETIME.SUB(3) 							 1							   DATETIME.SUB(3)

DateTime::sub - Subtracts an amount of days, months, years, hours, minutes and seconds from a DateTime object

       Object oriented style

SYNOPSIS
public DateTime DateTime::sub (DateInterval $interval) DESCRIPTION
Procedural style DateTime date_sub (DateTime $object, DateInterval $interval) Subtracts the specified DateInterval object from the specified DateTime object. PARAMETERS
o $object -Procedural style only: A DateTime object returned by date_create(3). The function modifies this object. o $interval - A DateInterval object RETURN VALUES
Returns the DateTime object for method chaining or FALSE on failure. EXAMPLES
Example #1 DateTime.sub(3) example Object oriented style <?php $date = new DateTime('2000-01-20'); $date->sub(new DateInterval('P10D')); echo $date->format('Y-m-d') . " "; ?> Procedural style <?php $date = date_create('2000-01-20'); date_sub($date, date_interval_create_from_date_string('10 days')); echo date_format($date, 'Y-m-d'); ?> The above examples will output: 2000-01-10 Example #2 Further DateTime.sub(3) examples <?php $date = new DateTime('2000-01-20'); $date->sub(new DateInterval('PT10H30S')); echo $date->format('Y-m-d H:i:s') . " "; $date = new DateTime('2000-01-20'); $date->sub(new DateInterval('P7Y5M4DT4H3M2S')); echo $date->format('Y-m-d H:i:s') . " "; ?> The above example will output: 2000-01-19 13:59:30 1992-08-15 19:56:58 Example #3 Beware when subtracting months <?php $date = new DateTime('2001-04-30'); $interval = new DateInterval('P1M'); $date->sub($interval); echo $date->format('Y-m-d') . " "; $date->sub($interval); echo $date->format('Y-m-d') . " "; ?> The above example will output: 2001-03-30 2001-03-02 NOTES
DateTime.modify(3) is an alternative when using PHP 5.2. SEE ALSO
DateTime.add(3), DateTime.diff(3), DateTime.modify(3). PHP Documentation Group DATETIME.SUB(3)
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