So my output would be a script containing the values in the text file:
I would like my script to repeat for each row in the text file. I think this can be accomplished with sed or awk, but unsure how to piece together the proper commands. Thanks so much.
Hello,
Following may help in same.
Output will be as follows. EDIT: Adding more solutions for same.
Thanks,
R. Singh
Last edited by RavinderSingh13; 09-26-2014 at 02:32 AM..
Reason: Added 2 more solutions for same
I need to replace the line containing "STAGE_DB" with the line
"STAGE_DB $DB # database that contains the table being loaded ($workingDB)"
Here $DB is passed during the runtime.
How can I do this?
Thanks,
Kousikan (2 Replies)
1.
how can i replace ' / ' with new line in shell script or sed ?
2.
how can set a conditon untill null in while loop
while ( i== null )
do
......
done (3 Replies)
Hi
I want to give the user the choice of whether or not they want to include a certain option when they run the script.
This is my getops:
while getopts " s: d: r f: e h " option
do
case $option in
f ) dsxfile="$OPTARG";;
d ) dbname="$OPTARG";;
s ) dsn="$OPTARG";;
r )... (0 Replies)
I have a file, from where I need to extract some data. But, the condition is like following :
The script will read line by line,while checking if any line starts with 'MN'. If found true, it looks for if the immediate line starts with 'PQ' or not. If its true then, extract few fields from that... (1 Reply)
i have few lines in a file... i am reading them in a while loop so a particular line is held is $line1.. consider a modified line is held in $line2.... i want to replace $line1 with $line2 in the same file... how to do it..?
i have come up till the below code
sed "s/$line1/$line2/g" tmpfile.sql... (5 Replies)
I am trying to delete lines in archived Apache httpd logs
Each line has the pattern:
<ip-address> - - <date-time> <document-request-URL> <http-response> <size-of-req'd-doc> <referring-document-URL>
This pattern is shown in the example of 6 lines from the log in the code box below. These 6... (1 Reply)
Hi How Are you?
I am doing fine!
I need to go now?
I will see you tomorrow!
Basically I need to replace the entire line containing "doing" with a blank line:
I need to the following output:
Hi How Are you?
I need to go now?
I will see you tomorrow!
Thanks in advance.... (1 Reply)
my requirement is,
consider a file output
cat output
blah sdjfhjkd jsdfhjksdh
sdfs 23423 sdfsdf sdf"sdfsdf"sdfsdf"""""dsf
hellow there
this doesnt look good
et cetc etc
etcetera
i want to replace a line of line number 4 ("this doesnt look good") with some other line
... (3 Replies)
All, I appreciate any help you can offer here as this is well beyond my grasp of awk/sed...
I have an input file similar to:
&LOG
&LOG Part: "@DB/TC10000021855/--F"
&LOG
&LOG
&LOG Part: "@DB/TC10000021852/--F"
&LOG Cloning_Action: RETAIN
&LOG Part: "@DB/TCCP000010713/--A"
&LOG
&LOG... (5 Replies)
Sed command to replace a line in a file using line number from the output of a pipe.
Is it possible to replace a whole line piped from someother command into a file at paritcular line...
here is some basic execution flow..
the line number is 412
lineNo=412
Now i have a line... (1 Reply)
Discussion started by: vivek d r
1 Replies
LEARN ABOUT CENTOS
shell-quote
SHELL-QUOTE(1) User Contributed Perl Documentation SHELL-QUOTE(1)NAME
shell-quote - quote arguments for safe use, unmodified in a shell command
SYNOPSIS
shell-quote [switch]... arg...
DESCRIPTION
shell-quote lets you pass arbitrary strings through the shell so that they won't be changed by the shell. This lets you process commands
or files with embedded white space or shell globbing characters safely. Here are a few examples.
EXAMPLES
ssh preserving args
When running a remote command with ssh, ssh doesn't preserve the separate arguments it receives. It just joins them with spaces and
passes them to "$SHELL -c". This doesn't work as intended:
ssh host touch 'hi there' # fails
It creates 2 files, hi and there. Instead, do this:
cmd=`shell-quote touch 'hi there'`
ssh host "$cmd"
This gives you just 1 file, hi there.
process find output
It's not ordinarily possible to process an arbitrary list of files output by find with a shell script. Anything you put in $IFS to
split up the output could legitimately be in a file's name. Here's how you can do it using shell-quote:
eval set -- `find -type f -print0 | xargs -0 shell-quote --`
debug shell scripts
shell-quote is better than echo for debugging shell scripts.
debug() {
[ -z "$debug" ] || shell-quote "debug:" "$@"
}
With echo you can't tell the difference between "debug 'foo bar'" and "debug foo bar", but with shell-quote you can.
save a command for later
shell-quote can be used to build up a shell command to run later. Say you want the user to be able to give you switches for a command
you're going to run. If you don't want the switches to be re-evaluated by the shell (which is usually a good idea, else there are
things the user can't pass through), you can do something like this:
user_switches=
while [ $# != 0 ]
do
case x$1 in
x--pass-through)
[ $# -gt 1 ] || die "need an argument for $1"
user_switches="$user_switches "`shell-quote -- "$2"`
shift;;
# process other switches
esac
shift
done
# later
eval "shell-quote some-command $user_switches my args"
OPTIONS --debug
Turn debugging on.
--help
Show the usage message and die.
--version
Show the version number and exit.
AVAILABILITY
The code is licensed under the GNU GPL. Check http://www.argon.org/~roderick/ or CPAN for updated versions.
AUTHOR
Roderick Schertler <roderick@argon.org>
perl v5.16.3 2010-06-11 SHELL-QUOTE(1)