Hi Guys,
Can you help me with a sed or a csh script that will have an output from the input below. Cutting the columns starting from the end of the line and not from the start of the line?
Sample1 - The underscore character "_" is actually a space...i need to put it as underscore here coz... (2 Replies)
I have a variable var which contains "ABCDEFDH"
Now I have to remove the first 4 characters that is "ABCD"
so my variable should contain only "DEFH"
plzz tell me how to do that .
i am using bash shell (1 Reply)
I have a script in a directory and want to search the directory before like follows:
i=0
for file in ../HN_*
do
echo $file
((i+=1))
echo $i
done
Currently I get following output:
../HN_2
1
../HN_3
2 (2 Replies)
i have this script that reads a file "listall_101111" where 101111 varies.
awk '{print $0,$1}' listall_101111 | sed -e 's/\(.*\).$/\1/g' | awk '{print $6,$2,$3,$4,$5}' | sort -nrk5 | nawk 'NR==1{m=$5;a++;b=(b)?b:$0;next}$5==m{a++;b=(b)?b:$0}END{for (i in a){print b,a}}' | grep -v ^LG | sort... (4 Replies)
Can we input two variable on single line that separate by space example user input "list jpg" it will list all jpg files in current directory (3 Replies)
Hello
I have a script:
path=test1
echo "${path%?}"
till this the program is successful in deleting hte last character i.e. "1" and displays an output --> test. After this how can i save this output to another variable. (2 Replies)
Hello everyone,
I am manipulating a large CSV file and am trying to read it into a program and started running into trouble. The have manually edited the file trying to make it correctly run through the program and have made progress. However, I am know stuck with an issue involving too many... (3 Replies)
I would like search and find a word (easily identified by 'key') from an xml file and then cut all of the tags out of the resulting line (anything between a < and a >) and display the remaining material. I am running Debian and mksh shell.
dictionary.sh:
#!/bin/sh
key='key="'$1'"><form'... (3 Replies)
Discussion started by: bedtime
3 Replies
LEARN ABOUT DEBIAN
paps
PAPS(1) General Commands Manual PAPS(1)NAME
paps - UTF-8 to PostScript converter using Pango
SYNOPSIS
paps [options] files...
DESCRIPTION
paps reads a UTF-8 encoded file and generates a PostScript language rendering of the file. The rendering is done by creating outline curves
through the pango ft2 backend.
OPTIONS
These programs follow the usual GNU command line syntax, with long options starting with two dashes (`-'). A summary of options is
included below.
--landscape
Landscape output. Default is portrait.
--columns=cl
Number of columns output. Default is 1.
Please notice this option isn't related to the terminal length as in a "80 culums terminal".
--font=desc
Set the font description. Default is Monospace 12.
--rtl Do right to left (RTL) layout.
--paper ps
Choose paper size. Known paper sizes are legal, letter and A4. Default is A4.
Postscript points
Each postscript point equals to 1/72 of an inch. 36 points are 1/2 of an inch.
--bottom-margin=bm
Set bottom margin. Default is 36 postscript points.
--top-margin=tm
Set top margin. Default is 36 postscript points.
--left-margin=lm
Set left margin. Default is 36 postscript points.
--right-margin=rm
Set right margin. Default is 36 postscript points.
--gutter-width=gw
Set gutter width. Default is 40 postscript points.
--help Show summary of options.
--header
Draw page header for each page.
--markup
Interpret the text as pango markup.
--lpi Set the lines per inch. This determines the line spacing.
--cpi Set the characters per inch. This is an alternative method of specifying the font size.
--stretch-chars
Indicates that characters should be stretched in the y-direction to fill up their vertical space. This is similar to the texttops
behaviour.
AUTHOR
paps was written by Dov Grobgeld <dov.grobgeld@gmail.com>.
This manual page was written by Lior Kaplan <kaplan@debian.org>, for the Debian project (but may be used by others).
April 17, 2006 PAPS(1)