Sponsored Content
Top Forums UNIX for Dummies Questions & Answers Echo does not work to append to a new line Post 302917289 by Corona688 on Monday 15th of September 2014 05:28:18 PM
Old 09-15-2014
Do not use echo -e, do not use echo -n.
Code:
printf "%s\n" "mystring"

This User Gave Thanks to Corona688 For This Post:
 

10 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

echo, append to end of file

I need the line printed with echo to append to eof of to exactly line, am i able to do that? i mean echo "sysctl -w lalala=1" > to end of file /etc/sysctl.conf or to the 21st line, if the line exist, open new line and insert text there. Thx.maybe i'm in wrong topic but anyway... (2 Replies)
Discussion started by: hachik
2 Replies

2. UNIX for Dummies Questions & Answers

bash pattern matching echo *[! '/' ] doesn't work

without using ls, just using echo so purely pattern matching I can say echo */ <-- lists directories but how would I match files? surely something like *!/ or * but neither work ? it seems like there isn't much that I can put in but surely i should be able to put any ascii... (1 Reply)
Discussion started by: james hanley
1 Replies

3. Shell Programming and Scripting

Append Status to echo'd line after process completes

Hello All, I'm very new to scripting and I'm writing a very simple script to restart a couple processes because I'm getting to lazy to cd between directories. This is pretty much my first script and I just want to add a little cosmetics to it. Here's what I have: #!/bin/ksh echo... (5 Replies)
Discussion started by: Setan
5 Replies

4. Shell Programming and Scripting

if [ -z echo foo | egrep -e 'regexp' != '' ] -> dont work

Hallo, I need to test a String (a special ip number-string). So I want to run that: ipadress=172.0.0.0 # for debugging: echo $ipadress | egrep -e '172\.?\.??\.??$' # the test that doesnt work if test -z `echo $ipadress | egrep -e '172\.?\.??\.??$'` != "" then echo "match" else... (1 Reply)
Discussion started by: wiseguy
1 Replies

5. Shell Programming and Scripting

echo $PWD doesn't work

I have entry in the my .profile like below, but still i see $PWD is not defied in my system export PS1=$LOGNAME@`hostname`':'$PWD'>' echo $PWD also gives me nothing, my env list also give no entry for PWD.Can someone help me setting PWD variable. I use /bin/sh (9 Replies)
Discussion started by: yesmani
9 Replies

6. Shell Programming and Scripting

shell script, echo doesn't work

#!/bin/sh something(){ echo "Inside something" echo $1 $2 } val=$(something "Hello " "world") Output expected: Inside somethingHello world But it's not echoing. (4 Replies)
Discussion started by: cola
4 Replies

7. UNIX for Dummies Questions & Answers

'echo dir_path | xargs cd' does not work?

Hi: how come this command does not work? the error message is: xargs: cd: No such file or directory yet, in the same time, 'echo dir_path | xargs ls' works. Does it work in bash? We use csh. Thanks. NB Phil (7 Replies)
Discussion started by: phil518
7 Replies

8. Shell Programming and Scripting

Color on echo output does not work

Hi, When I run: echo "\033I see hi in color, but if I run this color is not shown, why? (echo "\033Thanks Israel. ---------- Post updated at 05:17 AM ---------- Previous update was at 04:43 AM ---------- DONE!! I had to run more -v. Thanks (4 Replies)
Discussion started by: iga3725
4 Replies

9. Shell Programming and Scripting

echo doesn't work right

Hi,when I run my first shell script,I got something that doesn't work right. I wrote this code in the script. echo -e "Hello,World\a\n"But the screen print like this: -e Hello,World The "-e" wasn't supposed to be printed out. Can anyone help me out?:wall: Many thanks!:) (25 Replies)
Discussion started by: Demon
25 Replies

10. Shell Programming and Scripting

SED and Solaris Append line to the end of File does not work

Hello, I have to add a new line at the end of a File on Solaris-System: I think my script should be right, because I evaluated it to other threads. However the script does not what I am expected it should do. My file might look like this: Line1 Line2 Line3 And my script could... (7 Replies)
Discussion started by: Timo_HR
7 Replies
ECHO(3) 								 1								   ECHO(3)

echo - Output one or more strings

SYNOPSIS
void echo (string $arg1, [string $...]) DESCRIPTION
Outputs all parameters. echo is not actually a function (it is a language construct), so you are not required to use parentheses with it. echo (unlike some other language constructs) does not behave like a function, so it cannot always be used in the context of a function. Additionally, if you want to pass more than one parameter to echo, the parameters must not be enclosed within parentheses. echo also has a shortcut syntax, where you can immediately follow the opening tag with an equals sign. Prior to PHP 5.4.0, this short syn- tax only works with the short_open_tag configuration setting enabled. I have <?=$foo?> foo. PARAMETERS
o $arg1 - The parameter to output. o $... - RETURN VALUES
No value is returned. EXAMPLES
Example #1 echo examples <?php echo "Hello World"; echo "This spans multiple lines. The newlines will be output as well"; echo "This spans multiple lines. The newlines will be output as well."; echo "Escaping characters is done "Like this"."; // You can use variables inside of an echo statement $foo = "foobar"; $bar = "barbaz"; echo "foo is $foo"; // foo is foobar // You can also use arrays $baz = array("value" => "foo"); echo "this is {$baz['value']} !"; // this is foo ! // Using single quotes will print the variable name, not the value echo 'foo is $foo'; // foo is $foo // If you are not using any other characters, you can just echo variables echo $foo; // foobar echo $foo,$bar; // foobarbarbaz // Some people prefer passing multiple parameters to echo over concatenation. echo 'This ', 'string ', 'was ', 'made ', 'with multiple parameters.', chr(10); echo 'This ' . 'string ' . 'was ' . 'made ' . 'with concatenation.' . " "; echo <<<END This uses the "here document" syntax to output multiple lines with $variable interpolation. Note that the here document terminator must appear on a line with just a semicolon. no extra whitespace! END; // Because echo does not behave like a function, the following code is invalid. ($some_var) ? echo 'true' : echo 'false'; // However, the following examples will work: ($some_var) ? print 'true' : print 'false'; // print is also a construct, but // it behaves like a function, so // it may be used in this context. echo $some_var ? 'true': 'false'; // changing the statement around ?> NOTES
Note Because this is a language construct and not a function, it cannot be called using variable functions. SEE ALSO
print(3), printf(3), flush(3), Heredoc syntax. PHP Documentation Group ECHO(3)
All times are GMT -4. The time now is 05:59 AM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy