awk command optimization Post: 302917058

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Top Forums Shell Programming and Scripting awk command optimization Post 302917058 by SkySmart on Saturday 13th of September 2014 06:54:48 PM

09-13-2014

Registered User

Quote:

Originally Posted by shamrock

Well you could give this [g]awk a try...

Code:

gawk '{
    for (i=1; i<=NF; i++)
        if ($i ~ "^(error|fail|panic|accepted)$")
            a[$i]++
} END {
    for (i in a) {
        n++
        printf("%s=%s%s", i, a[i], (n < 4 ? ", " : "\n"))
    }
}' file

so this code seems to be doing what i need. however, it doesn't appear to be finding strings that have spaces in them. here's how i'm running it:

Code:

gawk '{
    for (i=1; i<=NF; i++)
        if ($i ~ "(error|fail|panic|open database|accepted)")
            a[$i]++
} END {
    for (i in a) {
        n++
        printf("%s=%s%s", i, a[i], (n < 4 ? ", " : "\n"))
    }
}' file

it finds every other string except the "open database" one. i tried replacing it with "open.*database" and that still didn't work. can this be tweaked to accept strings with spaces?

i also tried:

Code:

gawk '{
    for (i=1; i<=NF; i++)
        if ($i ~ "/error|fail|panic|open database|accepted/")
            a[$i]++
} END {
    for (i in a) {
        n++
        printf("%s=%s%s", i, a[i], (n < 4 ? ", " : "\n"))
    }
}' file

Last edited by SkySmart; 09-13-2014 at 08:00 PM..

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