09-12-2014
Quote:
Originally Posted by
miniviking10
Thank you my friend. This works. The only thing that did not work is the part I bolded in the quote. It keeps printing "n" at the end of the statement instead of doing a new line(which is what I think you're trying to do here?).
That's exactly what "\n" does inside a double-quoted string, yes.
Did you alter it in any way or double up the backslashes, etc? It really ought to work as-is.
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LEARN ABOUT LINUX
bswap_32
BSWAP(3) Linux Programmer's Manual BSWAP(3)
NAME
bswap_16, bswap_32, bswap_64 - reverse order of bytes
SYNOPSIS
#include <byteswap.h>
bswap_16(x);
bswap_32(x);
bswap_64(x);
DESCRIPTION
These macros return a value in which the order of the bytes in their 2-, 4-, or 8-byte arguments is reversed.
RETURN VALUE
These macros return the value of their argument with the bytes reversed.
ERRORS
These macros always succeed.
CONFORMING TO
These macros are GNU extensions.
EXAMPLE
The program below swaps the bytes of the 8-byte integer supplied as its command-line argument. The following shell session demonstrates
the use of the program:
$ ./a.out 0x0123456789abcdef
0x123456789abcdef ==> 0xefcdab8967452301
Program source
#include <stdio.h>
#include <stdint.h>
#include <stdlib.h>
#include <inttypes.h>
#include <byteswap.h>
int
main(int argc, char *argv[])
{
uint64_t x;
if (argc != 2) {
fprintf(stderr, "Usage: %s <num>
", argv[0]);
exit(EXIT_FAILURE);
}
x = strtoul(argv[1], NULL, 0);
printf("0x%" PRIx64 " ==> 0x%" PRIx64 "
", x, bswap_64(x));
exit(EXIT_SUCCESS);
}
SEE ALSO
byteorder(3), endian(3)
Linux 2019-03-06 BSWAP(3)