Hi Friends
I have a file
like
sample1.txt
------------
10998909.txt
10898990.txt
1898772222.txt
8980000000000.txt
I need to take first 3 characters of each line in a file and i need to print it '
like loop
109
108
189
898 (7 Replies)
I know this sounds simple, but I have a logfile with
> something
> something_else
> another_entry
...
how do I cut the first 2 characters off the left side? I tried to use
cut -c 1-2 somefile > someotherfile
but that just cut gave me the 2 left characters, I want to cut those out... (2 Replies)
Hi All,
Need to convert file names to upper case using tr command in Unix.
In a folder -> /apps/dd01/misc
there are two files like:
pi-abcd567sd.pdf
pi-efgh1.pdf
The output of should be like:
pi-ABCD567SD.pdf
pi-EFGH1.pdf
I have used the command to work as below:
for f... (3 Replies)
Guys,
can you help me in doing cut first 21 and 32-35 characters from file.
I tried with cut -c to cut first 21 characters ,It is succeeded.
But i need both first 21 and 32-35. (1 Reply)
hello everybody
i am looking for a shell to cut a flat file (with a long unique line) according to a certain number of characters and redirect every result to an output file.
here is an example
MyFile :
12 3 456 12 3 456 12 3 456 .....
and i took every 9-characters including BLANKS... (6 Replies)
Hi Gurus,
I am trying to execute the below command. However the output shows the value + path of the folder where the command is being executed. But I am only interested in the value but not the path.
du -hs /aps/inf/SeLogs
when I execute the above command, output is
32G... (5 Replies)
I need to cut the last seven characters of a variable length variable. The variable may be 7 characters or 70. I need to always be able to grab the last 7 characters. I looked at the cut command but it always seems to want to start at the beginning of a line, not the end and count backwards.
... (5 Replies)
Hi,
I would like to cut last 13 characters of a file name and take the rename the file name as follows:
Input:
A.DAT20110517033732
Output:
A.DAT
I have tried the following command and cut last 13 characters.
echo A.DAT20110517033732 | awk '{print substr($0, length($0)-13)}'
... (3 Replies)
Hi Everyone,
i have a file 1.txt
<a><a"" dd>aaaaauweopriuew</f><">!(^)!</aa></ff>
<a><a"" dd>bbbbbuweopriuew</f><">!(^*)!</aa></ff>
i know i can use
perl -p -i -e "s/>aaaaa/aa/g" 1.txt
perl -p -i -e "s/>bbbbb/bb/g" 1.txt
to acheive only keep the first two characters of the five characters,... (4 Replies)
Discussion started by: jimmy_y
4 Replies
LEARN ABOUT MINIX
cut
CUT(1) General Commands Manual CUT(1)NAME
cut - select out columns of a file
SYNOPSIS
cut [ -b | -c] list [file...]
cut -f list [-d delim] [ -s]
OPTIONS -b Cut specified bytes
-c Select out specific characters
-d Change the column delimiter to delim
-f Select out specific fields that are separated by the
-i Runs of delimiters count as one
-s Suppres lines with no delimiter characters, when used
EXAMPLES
cut -f 2 file # Extract field 2
cut -c 1-2,5 file # Extract character columns 1, 2, and 5
cut -c 1-5,7- file # Extract all columns except 6
DESCRIPTION
[file...]" delimiter character ( see delim)" with the -f option. Lines with no delimiters are passwd through untouched"
Cut extracts one or more fields or columns from a file and writes them on standard output. If the -f flag is used, the fields are sepa-
rated by a delimiter character, normally a tab, but can be changed using the -d flag. If the -c flag is used, specific columns can be
specified. The list can be comma or BLANK separated. The -f and -c flags are mutually exclusive. Note: The POSIX1003.2 standard requires
the option -b to cut out specific bytes in a file. It is intended for systems with multi byte characters (e.g. kanji), since MINIX uses
only one byte characters, this option is equivalent to -c. For the same reason, the option -n has no effect and is not listed in this man-
ual page.
SEE ALSO sed(1), awk(9).
CUT(1)