Hi there
i am trying to pass the result of a remote command into a variable into my script
ie
#!/bin/sh
var = `ssh remote_box 'uname'`
echo $var
but all i get back is
./script.sh: var: not found
However when i add a -x to put it into diag mode i get the following
+ ssh... (2 Replies)
Hi ,
I am trying following .
I need to get a result of an autosys cmd into a unix variable.
The autosys cmd is
autostatus -G jpm_day_today
Please help me in storing the value returned by this cmd into a unix variable.
Appreciate your time to read this post. (1 Reply)
Hi friends,
firstly, i can run following expression and i took 100 value.
sqlplus -s username/password@TTTEST @umt.sql
umt.sql exists "select t.deger from parametre t where t.id=30".
result of this query =100
i need to assign this value(100) to variable(for example x... (2 Replies)
Hi All,
How can i take the following code having three seds into a variable :
echo "$DateFileFormat" | sed 's/\./\\\\./g' | sed 's/\$/+/g' | sed 's/\#/'$job_date'/g'
I want to get the result stored in a script variable
i tried
var2=`echo "$DateFileFormat" | sed 's/\./\\\\./g' |... (4 Replies)
Hi all,
I'll try to get a result from a search with "awk" into a variable.
It works for those examples:
findfirstline=`awk 'BEGIN{ mycount = 1 } { if(mycount == 1 && /^Video/){ row=NR; print row; mycount = 0; }}' ${i}`
findlastline=`awk '/^Video/ {row=NR} END{print row}' ${i}`
But it... (6 Replies)
Hey everyone
I have a file 'agenda' which contains:
Object Day Month Year
Birthday 09 02 2012
i want to extract from a script the line which contains the day the user typed.
for example if he type 09 the line is showed using... (4 Replies)
Hi,
i have two variables i.e
lck_ckm_customer=ckm_customer and(present in some script A)
table=ckm_customer(present in script B)
in script B i am executing this part
if ; then
---
----
----
fi
Now, while comparing in my log file i am getting this result
if
but i... (2 Replies)
I have friends that this command worked perfectly, but I would like to save the result in a variable, which I have not achieved
var=prueba.txt
echo $var | cut -d "." -f 1
prueba
I need to do this but does not work me
salida=echo $var | cut -d "." -f 1
echo "result:$salida"
... (8 Replies)
Hi,
i have a source file and have 3 columns and separated by "|" .i want to split this 3 columns in different variable.When i am executing this values indivisually giving correct result but when the same execute inside a for loop,it's giving issues.
Src file(jjj.txt)
-------... (8 Replies)
Discussion started by: raju2016
8 Replies
LEARN ABOUT CENTOS
shell-quote
SHELL-QUOTE(1) User Contributed Perl Documentation SHELL-QUOTE(1)NAME
shell-quote - quote arguments for safe use, unmodified in a shell command
SYNOPSIS
shell-quote [switch]... arg...
DESCRIPTION
shell-quote lets you pass arbitrary strings through the shell so that they won't be changed by the shell. This lets you process commands
or files with embedded white space or shell globbing characters safely. Here are a few examples.
EXAMPLES
ssh preserving args
When running a remote command with ssh, ssh doesn't preserve the separate arguments it receives. It just joins them with spaces and
passes them to "$SHELL -c". This doesn't work as intended:
ssh host touch 'hi there' # fails
It creates 2 files, hi and there. Instead, do this:
cmd=`shell-quote touch 'hi there'`
ssh host "$cmd"
This gives you just 1 file, hi there.
process find output
It's not ordinarily possible to process an arbitrary list of files output by find with a shell script. Anything you put in $IFS to
split up the output could legitimately be in a file's name. Here's how you can do it using shell-quote:
eval set -- `find -type f -print0 | xargs -0 shell-quote --`
debug shell scripts
shell-quote is better than echo for debugging shell scripts.
debug() {
[ -z "$debug" ] || shell-quote "debug:" "$@"
}
With echo you can't tell the difference between "debug 'foo bar'" and "debug foo bar", but with shell-quote you can.
save a command for later
shell-quote can be used to build up a shell command to run later. Say you want the user to be able to give you switches for a command
you're going to run. If you don't want the switches to be re-evaluated by the shell (which is usually a good idea, else there are
things the user can't pass through), you can do something like this:
user_switches=
while [ $# != 0 ]
do
case x$1 in
x--pass-through)
[ $# -gt 1 ] || die "need an argument for $1"
user_switches="$user_switches "`shell-quote -- "$2"`
shift;;
# process other switches
esac
shift
done
# later
eval "shell-quote some-command $user_switches my args"
OPTIONS --debug
Turn debugging on.
--help
Show the usage message and die.
--version
Show the version number and exit.
AVAILABILITY
The code is licensed under the GNU GPL. Check http://www.argon.org/~roderick/ or CPAN for updated versions.
AUTHOR
Roderick Schertler <roderick@argon.org>
perl v5.16.3 2010-06-11 SHELL-QUOTE(1)