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Top Forums Shell Programming and Scripting Compare two arrays by values [BASH] Post 302914476 by RudiC on Tuesday 26th of August 2014 05:35:18 AM
Old 08-26-2014
I'm afraid you can't escape comparing the arrays element by element, in e.g. a for loop. If you show us what you tried and where you got stuck, we'll be glad to help.
 

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lreplace(n)						       Tcl Built-In Commands						       lreplace(n)

__________________________________________________________________________________________________________________________________________________

NAME
lreplace - Replace elements in a list with new elements SYNOPSIS
lreplace list first last ?element element ...? _________________________________________________________________ DESCRIPTION
lreplace returns a new list formed by replacing one or more elements of list with the element arguments. first and last specify the first and last index of the range of elements to replace. 0 refers to the first element of the list, and end (or any abbreviation of it) may be used to refer to the last element of the list. If list is empty, then first and last are ignored. If first is less than zero, it is considered to refer to the first element of the list. For non-empty lists, the element indicated by first must exist. If last is less than zero but greater than first, then any specified elements will be prepended to the list. If last is less than first then no elements are deleted; the new elements are simply inserted before first. The element arguments specify zero or more new arguments to be added to the list in place of those that were deleted. Each element argu- ment will become a separate element of the list. If no element arguments are specified, then the elements between first and last are sim- ply deleted. If list is empty, any element arguments are added to the end of the list. SEE ALSO
lappend(n), lindex(n), linsert(n), list(n), llength(n), lrange(n), lsearch(n), lsort(n) KEYWORDS
element, list, replace Tcl 7.4 lreplace(n)
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