Help with Passing the Output of grep to sed command - to find and replace a string in a file.
I have a file example.txt as follows :
I need to automatically update the date (20140818) in the above file, by getting the new date as argument, using a shell script.
(It would even be better if I could pass both the file name, in which the date should be updated, and date as arguments)
I tried greping the line where the date occurs using
which gives the output as :
Now I don't know how to give this output as input to a sed command and replace the date(only date, the numeric part).
Or, is there any other alternative way to achieve this ??
Hello all
Im performing find + grep operation that looks like this :
find . -name "*.dsp" | xargs grep -on Project.lib | grep -v ':0'
and I like to add to this one liner the possibility to replace the string " Project.lib" that found ( more then once in file ) with "Example.lib"
how can I do... (0 Replies)
how to use sed command to find and replace a directory
i have a file.. which contains lot of paths ...
for eg.. file contains..
/usr/kk/rr/12345/1
/usr/kk/rr/12345/2
/usr/kk/rr/12345/3
/usr/kk/rr/12345/4
/usr/kk/rr/12345/5
/usr/kk/rr/12345/6
/usr/kk/rr/12345/7... (1 Reply)
Hi all,
I know this question has probably been answered before, but I am struggling with this problem, even after googling a million pages.
In a file named rdmt.conf
I need a single character replaced, the number in the line below
CUR_OC4J_ID=1
It will always appear after... (3 Replies)
Hi Everyone,
I am new to this forum and new to sed/awk programming too !!
I need to find particular string in file1(text file) and replace it with a value from another text file(file2) the file2 has only one line and the value to be replaced with is in the second column.
file 1:
(assert (=... (21 Replies)
QUESTION1:
How do you grep only an exact string. I am using Solaris10 and do not have any GNU products installed.
Contents of car.txt
CAR1_KEY0
CAR1_KEY1
CAR2_KEY0
CAR2_KEY1
CAR1_KEY10
CURRENT COMMAND LINE: WHERE VARIABLE CAR_NUMBER=1 AND KEY_NUMBER=1
grep... (1 Reply)
here is what i want to achieve... consider a file contains below contents. the file size is large about 60mb
cat dump.sql
INSERT INTO `table1` (`id`, `action`, `date`, `descrip`, `lastModified`) VALUES (1,'Change','2011-05-05 00:00:00','Account Updated','2012-02-10... (10 Replies)
Grep and Sed (replace string in patterned lines)
Hi all,
I want to grep for "PATTERN" and only if "PATTERN" is in a line, this line shall be used as replacement input e.g. for SED.
I don't get it running in one line.
NOT RUNNING - just first idea... I don't know how to redirect grep... (2 Replies)
Some help please:
Need to find string ||(everything in front of it)B0300|| and replace it with ||0|| globally
In:
16112121||||0||0||0||0||0||52||52||0||0||0||0||1507200053342B0300||1507200053342B0300||0||0||0||0700
Out:
16112121||||0||0||0||0||0||52||52||0||0||0||0||0||0||0||0||0||0700
... (4 Replies)
how to search and replace string in column in file with command sed or other
search "INC0000003.in" and replace column 4 = "W"
$ cat file.txt
INC0000001.in|20150120|Y|N|N
INC0000002.in|20150120|Y|N|N
INC0000003.in|20150120|Y|N|N
INC0000004.in|20150120|Y|N|Noutput... (4 Replies)
I have a file comp.pkglist which mention package version and release . In 'version change' and 'release change' line there are two versions 'old' and 'new' Version Change: --> Release Change: -->
cat comp.pkglist
Package list: nss-util-devel-3.28.4-1.el6_9.x86_64
Version Change: 3.28.4 -->... (1 Reply)
Discussion started by: Paras Pandey
1 Replies
LEARN ABOUT PHP
datetime.sub
DATETIME.SUB(3) 1 DATETIME.SUB(3)DateTime::sub - Subtracts an amount of days, months, years, hours, minutes and seconds from a DateTime object
Object oriented style
SYNOPSIS
public DateTime DateTime::sub (DateInterval $interval)
DESCRIPTION
Procedural style
DateTime date_sub (DateTime $object, DateInterval $interval)
Subtracts the specified DateInterval object from the specified DateTime object.
PARAMETERS
o $object
-Procedural style only: A DateTime object returned by date_create(3). The function modifies this object.
o $interval
- A DateInterval object
RETURN VALUES
Returns the DateTime object for method chaining or FALSE on failure.
EXAMPLES
Example #1
DateTime.sub(3) example
Object oriented style
<?php
$date = new DateTime('2000-01-20');
$date->sub(new DateInterval('P10D'));
echo $date->format('Y-m-d') . "
";
?>
Procedural style
<?php
$date = date_create('2000-01-20');
date_sub($date, date_interval_create_from_date_string('10 days'));
echo date_format($date, 'Y-m-d');
?>
The above examples will output:
2000-01-10
Example #2
Further DateTime.sub(3) examples
<?php
$date = new DateTime('2000-01-20');
$date->sub(new DateInterval('PT10H30S'));
echo $date->format('Y-m-d H:i:s') . "
";
$date = new DateTime('2000-01-20');
$date->sub(new DateInterval('P7Y5M4DT4H3M2S'));
echo $date->format('Y-m-d H:i:s') . "
";
?>
The above example will output:
2000-01-19 13:59:30
1992-08-15 19:56:58
Example #3
Beware when subtracting months
<?php
$date = new DateTime('2001-04-30');
$interval = new DateInterval('P1M');
$date->sub($interval);
echo $date->format('Y-m-d') . "
";
$date->sub($interval);
echo $date->format('Y-m-d') . "
";
?>
The above example will output:
2001-03-30
2001-03-02
NOTES DateTime.modify(3) is an alternative when using PHP 5.2.
SEE ALSO DateTime.add(3), DateTime.diff(3), DateTime.modify(3).
PHP Documentation Group DATETIME.SUB(3)