From the command line:
works as expected
However in a script:
the following is returned
Some help would be appreciated. I have no idea where I have gone wrong. Thanks.
Note that in the successful ls, the output does not contain a backslash character before the space. In that ls command, you used a backslash to escape the space to keep the shell from treating it as two filename operands.
In the cases that failed you quoted the filenames AND escaped the space. You need to do one or the other; not both. If at all possible, NEVER create filenames that contain a space, tab, or newline character. To solve the problem in this case, remove the \ character from the quoted strings when you assign the value to sourcefile. That is, change:
to:
This User Gave Thanks to Don Cragun For This Post:
Hi All,
I'm trying to concoct a bash script to use with a Puppet Implementation that will accept a hostname and break it down into variables.
For example, my hostnames look like this --> machinename-group-building.example.com
I'm looking for a way in the script to read until the first... (4 Replies)
Is it possible to have a bash script pick the highest and lowest values of four variables? I've been googling for this but haven't come up with anything. I have a script that assigns variables ($c0, $c1, $c2, and $c3) based on the coretemps from grep/sed statements of sensors. I'd like to also... (5 Replies)
I am using variable to give the location of the file I am using but I get error.
Here is the code:
LogFile=/tmp/log.email
echo -e "could not close the service - error number $error \n" > $LogFile
well this is not all the code but is enough because the problem start when I try to use the... (3 Replies)
I have a following problem:
#!/bin/bash
NUM=`cat accounts | wc -l`;
for i in {1..$NUM}
do
account=`awk "NR==$i" accounts`;
echo -e "\nAccount: $account\n";
sudo ./backup_maildir $account;
done "accounts" is a file with regular e-mail addresses, one in each line.... (2 Replies)
Hello, I am new to the whole "scripting" thing. Below is the script that I have so far and where i need the Variables to go (VAR#)
#!/bin/bash
#Sample Script
VAR1=
echo "Choose an option: 1) Create a file. 2) Delete a file. 3) Move a file."
read VAR1
case $VAR1 in
1)
echo "Pick... (4 Replies)
Hi all guys,
how you can read in thread title, I'm deploying a bash script in which I have to export some variables inside it.
But (I think you know) the export command works only inside the script and so, on exit command, the variables aren't set like I set inside the script.
Consequently in... (8 Replies)
Hello, my problem is simple & I searched a lot but I couldn't find anything about it:
Basically I'd like to pass $i to a variable, $i being the positional variable; but it is unknown in the beginning so I can't do it like eg. myvar=$3, it HAS to be the "i"..
First, I tried myvar=$($i) ... (8 Replies)
Hi all,
I want to dynamically set variables in a bash script. I made a naive attempt in a while loop that hopefully can clarify the idea.
n=0; echo "$lst" | while read p; do n=$(($n+1)); p"$n"="$p"; done
The error message is:
bash: p1=line1: command not found
bash: p2=line2: command... (8 Replies)
Hello experts!
I have a file1 with the following format (yr,day, month, hour,minute):
201201132435
201202141210
201304132030
201410100110
...
What i want to do is to assign variables and then use them in the curl command to download the text of each event from a web page.
What I have... (6 Replies)
#!/bin/bash
X=$(</home/cogiz/computerhand.txt) # (3S 8C 2H 6D QC 8S 4H 5H)
Y=$(</home/cogiz/topcardinplay.txt) # KS
A=( "${Y::1}" )
B=( "${Y:1}" )
for e in ${X}; do
if ]; then # searching for valid cards K,S or 8
... (0 Replies)