Get first four characters from the variable name Post: 302912964

10 More Discussions You Might Find Interesting

1. UNIX for Dummies Questions & Answers

To get the characters from a variable

Hi , I need to get the specified word from the variable.can some one help me out in this ? input=ASD34567P i need to get the value as : output1=34567 So i need to ignore the last character and get the remaining values. THANKS IN ADVANCE.

2. UNIX for Dummies Questions & Answers

extract characters from a variable

Hi All, I have scenario as below, I want to cut the characters and store it variable2.. and want to display the variable2.. as shown below... eg: the size may differs , i am show just an example..... numbers are not fixed in variable1..i want to extract characters and...

3. Shell Programming and Scripting

Cutting characters in a variable

I have a variable var which contains "ABCDEFDH" Now I have to remove the first 4 characters that is "ABCD" so my variable should contain only "DEFH" plzz tell me how to do that . i am using bash shell

4. Shell Programming and Scripting

Stripping characters from a variable

I'm using a shell script to get user input with this command: read UserInput I would then like to take the "UserInput" variable and strip out all of the following characters, regardless of where they appear in the variable or how many occurrences there are: \/":|<>+=;,?*@ I'm not sure...

5. Shell Programming and Scripting

Cut last 7 characters of a variable

I need to cut the last seven characters of a variable length variable. The variable may be 7 characters or 70. I need to always be able to grab the last 7 characters. I looked at the cut command but it always seems to want to start at the beginning of a line, not the end and count backwards. ...

6. Shell Programming and Scripting

getting first two characters of variable

From a shell script, I'm trying to get the first two characters of an environment variable. If I type at the command promot: XX=`echo $MYVAR | cut -c1-2` echo $XX It works just fine However, if I execute the exact same thing from a shell script, I get: cut: you must specify a list of...

7. Shell Programming and Scripting

Variable being stored with additional characters

I am trying to store a string value to a temporary variable within my script. When I run the command manually it returns the expected value, but from the script an additional "\r" is at the end. tCurrentStatus=`cat ${tPC_status} | grep 'Current status' | awk '{print $NF}'` output: cat...

8. Shell Programming and Scripting

Unset variable with characters in value

I have a script with a $PASSWORD variable. I unset it right after using it, just to minimize the chance it could be left around for a snooper. That worked just fine... until I used a password with a value of "P@ssw0rd" Now, unset (even with -f, even with the variable enquoted) tells me: unset:...

9. Shell Programming and Scripting

[Solved] Count characters of variable from right

My variable is something like: f="/Volumes/VERVE/MOOTON_CALL/01_shots/XX/xx0195/Projects/program/rs0195_v400001.aep" I use ${f:63:6} to call "rs0195" as characters counted from the left, but it'd be so much easier to count from the right. If ${f:95:10} counts from the left, what would...

10. Shell Programming and Scripting

Escape characters in a variable

Debian 9 64x - LXDE How can i disable escape sequences in a variable? #!/bin/bash #mainscript . "./links.bash" echo "$red_start This text should be red $color_end"#!/bin/bash #links.bash #colors red_start="\eOutput that i get: \e Output expected: This text should be...

LEARN ABOUT NETBSD

zegrep

ZGREP(1)						    BSD General Commands Manual 						  ZGREP(1)

NAME

     zgrep, zegrep, zfgrep -- print lines matching a pattern in gzip-compressed files

SYNOPSIS

     zgrep [grep-flags] [--] pattern [files ...]

     zegrep [grep-flags] [--] pattern [file ...]

     zfgrep [grep-flags] [--] pattern [file ...]

DESCRIPTION

     zgrep runs grep(1) on files or stdin, if no files argument is given, after decompressing them with zcat(1).

     The grep-flags and pattern arguments are passed on to grep(1).  If an -e flag is found in the grep-flags, zgrep will not look for a pattern
     argument.

     zegrep calls egrep(1), while zfgrep calls fgrep(1).

EXIT STATUS

     In case of missing arguments or missing pattern, 1 will be returned, otherwise 0.

SEE ALSO

     egrep(1), fgrep(1), grep(1), gzip(1), zcat(1)

AUTHORS

     Thomas Klausner <wiz@NetBSD.org>

BSD
								 December 28, 2003							       BSD

10 More Discussions You Might Find Interesting

1. UNIX for Dummies Questions & Answers

To get the characters from a variable

Discussion started by: ithirak17

2. UNIX for Dummies Questions & Answers

extract characters from a variable

Discussion started by: G.K.K

3. Shell Programming and Scripting

Cutting characters in a variable

Discussion started by: cynosure2009

4. Shell Programming and Scripting

Stripping characters from a variable

Discussion started by: nrogers64