Hi all,
Does anybody know or guide me on how to remove the first N bytes and the last N bytes from a binary file? Is there any AWK or SED or any command that I can use to achieve this?
Your help is greatly appreciated!!
Best Regards,
Naveen. (1 Reply)
I am creating ASCII file from Oracle procedure into Unix box.
I undertstand there is NO CRLF as I am writing it into one complete string .. but need to know what is best way to format the file with 80bytes per line only before handing over to another program.
Thanks in advance
regards... (14 Replies)
Hi All,
I want to find zero byte files in the given folder for the given day.
I know we can use find . -size 0 -mtime 0
But is there an option for file creation.?
ls -lart | grep ' 0 Apr 24' will also work.
Also is there any alternative using awk ?
I want to know how to use awk in... (1 Reply)
Hi,
I have packed fields for which I am trying to print bytes. when I try cut -b2 it does print the 2nd byte besides that it also prints additional byte that I am not aware off:confused: data looks something like this
Input:
135
246
when I try cut -b2 it gives me
30
4A
but I... (12 Replies)
While running script I am getting an error like
Few lines in data are not being processed.
After googling it I came to know that adding such line would give some memory to it
ini_set("memory_limit","64M");
my input file size is 1 GB.
Is that memory limit is based on RAM we have on... (1 Reply)
Hi,
If I want to copy a 1024 byte data stream in to the target location in 3-bytes chunk, I guess I can use the following script.
dd bs=1024 count=3 if=/src of=/dest
But, I would like to know, how to do it via a C program. I have tried this with memcpy(), that did not help. (3 Replies)
Hello guys. I really hope someone will help me with this one..
So, I have to write this script who:
- creates a file home/student/vmdisk of 10 mb
- formats that file to ext3
- mounts that partition to /mnt/partition
- creates a file /mnt/partition/data. In this file, there will... (1 Reply)
hello,
suppose, entered input is of 1-40 bytes, i need it to be converted to 40 bytes exactly.
example: if i have entered my name anywhere between 1-40 i want it to be stored with 40 bytes exactly.
enter your name:
donald duck (this is of 11 bytes)
expected is as below - display 11... (3 Replies)
is there a better way to do this:
head -c 10000k /var/dump.log | head -c 6000k
unfortunately, the "-c" option is not available on sun solaris. so i'm looking at "dd". but i dont know how to use it to achieve the same exact goal as the above head command.
this needs to work on both solaris... (5 Replies)
A byte is the smallest unit of storage which can be accessed in a computer's memory- either in RAM or ROM.It also holds exactly 8 bits.But its old view one byte was sufficient to hold one 8 bit character.Modern days especially on .NET or international versions of Win 32, 16 bits is needed.
... (2 Replies)
Discussion started by: stoudtLion
2 Replies
LEARN ABOUT MOJAVE
net::ldap::control::postread5.18
Net::LDAP::Control::PostRead(3) User Contributed Perl Documentation Net::LDAP::Control::PostRead(3)NAME
Net::LDAP::Control::PostRead - LDAPv3 Post-Read control object
SYNOPSIS
use Net::LDAP;
use Net::LDAP::Control::PostRead;
use Net::LDAP::Constant qw( LDAP_CONTROL_POSTREAD LDAP_SUCCESS );
$ldap = Net::LDAP->new( "ldap.mydomain.eg" );
$postread = Net::LDAP::Control::PostRead->new( attrs => [ qw/givenName/ ] );
my $mesg = $ldap->modify( "cn=Barbara Jensen, o=University of Michigan, c=US",
replace => { givenName => "Babs" },
control => $postread );
if ($mesg->code eq LDAP_SUCCESS) {
my ($afterwards) = $mesg->control( LDAP_CONTROL_PREREAD );
my $entry = $afterwards ? $afterwards->entry() : undef;
if ($entry) {
print "givenName changed to '" .
join("', '", $entry->get_value(givenName") .
"' to 'Babs'
");
}
}
DESCRIPTION
"Net::LDAP::Control::PostRead" provides an interface for the creation and manipulation of objects that represent the "Post-Read Controls"
as described by RFC 4527.
In modification operations, the "Post-Read request control" indicates to the server that a copy of the modified entry after the update is
to be returned. After the successful completion of the operation, the accompanying "Post-Read response control" allows one to retrieve the
updated value from the server's response.
One use case of this control may be to obtain values of operational attributes, such as the "entryUUID" and "modifyTimestamp" attributes,
updated by the server as part of the update operation.
CONSTRUCTOR ARGUMENTS
In addition to the constructor arguments described in Net::LDAP::Control the following are provided.
attrs => [ ATTR, ... ]
A list of attributes to be returned in the entry returned in the response control.
If absent, all attributes are returned.
Operational attributes may be included in the list by explicitly asking for them or by using special "+" feature (provided the server
supports this feature).
METHODS
As with Net::LDAP::Control each constructor argument described above is also available as a method on the object which will return the
current value for the attribute if called without an argument, and set a new value for the attribute if called with an argument.
In addition to these methods, the control also supports the following method:
entry ()
Returns the entry from the response control in the response message to the LDAP request that contained the request control.
The result is either a Net::LDAP::Entry object or undefined.
SEE ALSO
Net::LDAP, Net::LDAP::Control, http://www.ietf.org/rfc/rfc4527.txt
AUTHOR
Peter Marschall <peter@adpm.de>
Please report any bugs, or post any suggestions, to the perl-ldap mailing list <perl-ldap@perl.org>
COPYRIGHT
Copyright (c) 2008,2011 Peter Marschall. All rights reserved. This program is free software; you can redistribute it and/or modify it under
the same terms as Perl itself.
perl v5.18.2 2013-07-21 Net::LDAP::Control::PostRead(3)