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Full Discussion: How do i find "&variable[0]" using grep -r?
Top Forums Shell Programming and Scripting How do i find "&variable[0]" using grep -r? Post 302911959 by Don Cragun on Monday 4th of August 2014 11:49:05 PM
Old 08-05-2014
Quote:
Originally Posted by Scrutinizer
Note that grep -r statement will not find *.c files in subdirectories. The find statement will also fail to do that if the are any *.c files present in the current directory . In both cases *.c is expanded by the shell and the the result is provided as parameters to the command. To find all *.c files *.c needs to be quoted:
Code:
find . -name '*.c' -exec grep -E '&[[:alpha:]]+\[[0-9]+\]' {} +

Another thing is that xargs will break things if there are spaces in the filename. The example shows how it could be done without xargs, by using -exec . The + sign makes it at least as efficient as xargs
Note that with either find ... -exec ... + or with xargs, if only one matching file is found or if there are enough matching files to invoke grep multiple times and the last invocation only passes one filename to grep, the filename will not be printed along with the matching line. To protect against this rare case, add another file operand that you know will never match your pattern:
Code:
find . -name '*.c' -exec grep -E '&[[:alpha:]]+\[[0-9]+\]' /dev/null {} +

Does any of your code contain array variables with underscores or digits in their names? If so, maybe you want:
Code:
find . -name '*.c' -exec grep -E '&[_[:alpha:]][_[:alnum:]]*\[[0-9]+\]' /dev/null {} +

This User Gave Thanks to Don Cragun For This Post:
CarloM
 

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