Sponsored Content
Full Discussion: Sorting of YYYY-MM-DD
Top Forums Shell Programming and Scripting Sorting of YYYY-MM-DD Post 302911304 by maverick_here on Thursday 31st of July 2014 04:27:22 AM
Old 07-31-2014
Thank you Don

I have used

Code:
awk '{print $NF}' | sort

works absolutely fine !

However when I use it with the collective output it does not.

Example

Code:
 18      9150123 bytes      8935.67 KB    8.72624 MB     /var/log/sa     root   root     2014-07-31
 6       53170 bytes      51.9238 KB    0.0507069 MB     /var/log/xen    root   root     2014-07-25
 0       0 bytes      0 KB    0 MB       /var/log/xen/console    root   root     2013-05-21
 33      13332227 bytes      13019.8 KB    12.7146 MB    /var/log/nmon   nobody nobody   2014-07-31
 0       0 bytes      0 KB    0 MB       /var/log/squid          squid  squid    2010-03-31
 0       0 bytes      0 KB    0 MB       /var/log/iptraf         root   root     2007-03-14
 1       1448 bytes      1.41406 KB    0.00138092 MB     /var/log/mail   root   root     2011-08-11
 3       0 bytes      0 KB    0 MB       /var/log/news   news   news     2012-08-31
 0       0 bytes      0 KB    0 MB       /var/log/news/OLD       news   news     2010-01-27
 1       100189 bytes      97.8408 KB    0.0955477 MB    /var/log/mongo          mongod mongod   2013-10-22

Any ideas
#################################################################################################### #################################

Found what works for me

Code:
[root@#####bin]# sh get.sh -d /var/log  | sort -s -k 11.1,11.4 -k 11.6,11.7 -k 11.9,11.10 -k11.10 | awk '{print $11}'
2007-03-14
2007-11-11
2007-11-11
2009-01-21
2009-09-20
2010-01-27
2010-03-31
2011-08-11
2012-08-31
2012-08-31
2012-08-31
2013-02-17
2013-02-21
2013-02-28
2013-02-28
2013-02-28
2013-02-28
2013-04-23
2013-05-21
2013-10-22
2014-03-18
2014-04-27
2014-07-05
2014-07-24
2014-07-25
2014-07-25
2014-07-27
2014-07-27
2014-07-31
2014-07-31
2014-07-31


Many thanks

Last edited by maverick_here; 07-31-2014 at 05:51 AM.. Reason: Found solution
 

10 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

Change Date from dd-mmm-yyyy to mm/dd/yyyy

I want to change a date from format dd-mmm-yyyy to mm/dd/yyyy. Is there a way to do this with sed or do you have to write a case statement to convert JAN to 01? Thanks (9 Replies)
Discussion started by: stringzz
9 Replies

2. Shell Programming and Scripting

converting the date field from dd/mm/yyyy to yyyy/mm/dd

How to convert the date field from dd/mm/yyyy to yyyy/mm/dd in unix my script will generate text file which have two fields one is date and another is name of the server for example this is sample date which I have to sort based on older to newer date the problem is when I found out sort will... (4 Replies)
Discussion started by: pareshan
4 Replies

3. Shell Programming and Scripting

Convert DD-MMM-YYYY to MM-DD-YYYY

I have a file which has 100k+ records like this abc,05-JUN-1974,def,lkj,aaa def,11-SEP-1975,ghj,dis,dea I want to convert ex 05-JUN-1974 to 06/05/1974 Please help me with awk script to convert the whole file into MM-DD-YYYY Thank you! (2 Replies)
Discussion started by: nuthalapati
2 Replies

4. Shell Programming and Scripting

Sed: zero-padding dates (or: convert d/m/yyyy to dd/mm/yyyy)

Hi all I have some pipe-separated data in the form: 5/12/2008 00:00:00|31/1/2009 00:00:00|SOMESTUFF|OTHERSTUFF 12/31/2008 00:00:00|15/1/2009 00:00:00|MORESTUFF|REMAININGSTUFF 1/1/1023 00:00:00|16/5/2047 00:00:00|THEREST|YETMORE I need to zero-pad the single-digit days and months, using... (3 Replies)
Discussion started by: jgrogan
3 Replies

5. Shell Programming and Scripting

convert d/m/yyyy to YYYY-MM-DD

My csv has data like this x,x,3452,2/18/1986,abc x,g,19711,1/24/1986,abc i want to replace date in the following format YYYY-mm-dd how do i convert using awk script ? (8 Replies)
Discussion started by: nuthalapati
8 Replies

6. Shell Programming and Scripting

change date format from yyyy/mm/dd to dd/mm/yyyy

(Attention: Green PHP newbie !) I have an online inquiry form, delivering a date in the form yyyy/mm/dd to my feedback form. If the content passes several checks, the form sends an e-mail to me. All works fine. I just would like to receive the date in the form dd/mm/yyyy. I tried with some code,... (6 Replies)
Discussion started by: keyboarder
6 Replies

7. Shell Programming and Scripting

Converting date DD MM YYYY to DD MON YYYY

Hello, I am writing a script that parses different logs and produces one. In the source files, the date is in DD MM YYYY HH24:MI:SS format. In the output, it should be in DD MON YYY HH24:MI:SS (ie 25 Jan 2010 16:10:10) To extract the dates, I am using shell substrings, i.e.: read line ... (4 Replies)
Discussion started by: Adamm
4 Replies

8. Shell Programming and Scripting

Date conversion help from dd/mm/yyyy to dd/Mon/yyyy i.e. 28/10/2012 to 28/Oct/2012

Hi I have a problem with Date format in my code. 1st I am trying to convert today's date to yesterday's using YESTERDAY3=`perl -e '@y=localtime(time()-86400); printf "%04d/%02d/%02d",$y+1900,$y+1,$y;$y;'` And once it is done I am trying to using the yesterday date in a grep command to... (3 Replies)
Discussion started by: nithinankam
3 Replies

9. UNIX for Dummies Questions & Answers

Epoch date to YYYY/MM/DD or MM/DD/YYYY

I've seen a lot of posts on this and have tried the following: echo 1257000000| perl -e '($d,$m,$y)=(localtime(time-86400));$m+=1;$y+=1900;printf "$y/$m/$d\n";' But I am unable to convert a past Epoch date into a format such as YYYY/MM/DD or MM/DD/YYYY. I am using bash and don't know... (4 Replies)
Discussion started by: newbie2010
4 Replies

10. Shell Programming and Scripting

Date format YYYY/MM/DD to DD/MM/YYYY

I am getting output of YYYY-MM-DD and want to change this to DD/MM/YYYY. When am running the query in 'Todd' to_date(column_name,'DD/MM/YYYY') am getting the required o/p of DD/MM/YYYY, But when am executing the same query(Netezza) in linux server(bash) am getting the output of YYYY-MM-DD file... (3 Replies)
Discussion started by: Roozo
3 Replies
SA2(8)								Linux User's Manual							    SA2(8)

NAME
sa2 - Write a daily report in the /var/log/sysstat directory. SYNOPSIS
/usr/lib/sysstat/sa2 DESCRIPTION
The sa2 command is a shell procedure variant of the sar command which writes a daily report in the /var/log/sysstat/sardd file, where the dd parameter indicates the current day. The sa2 command handles all of the flags and parameters of the sar command. The sa2 command is designed to be started automatically by the cron command. EXAMPLES
To run the sa2 command daily, place the following entry in your root or adm crontab file: 5 19 * * 1-5 /usr/lib/sysstat/sa2 -A & This will generate a daily report called /var/log/sysstat/sardd It will also remove reports more than one week old. Debian note The Debian sysstat package has already placed such an entry in your system crontab. Please refer to the /usr/share/doc/sys- stat/README.Debian file for details. FILES
/var/log/sysstat/sardd Indicate the daily report file, where the dd parameter is a number representing the day of the month. AUTHOR
Sebastien Godard (sysstat <at> orange.fr) SEE ALSO
sar(1), sadc(8), sa1(8), sadf(1) http://pagesperso-orange.fr/sebastien.godard/ Linux AUGUST 2010 SA2(8)
All times are GMT -4. The time now is 01:05 AM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy