I want to change a date from format dd-mmm-yyyy to mm/dd/yyyy. Is there a way to do this with sed or do you have to write a case statement to convert JAN to 01? Thanks (9 Replies)
How to convert the date field from dd/mm/yyyy to yyyy/mm/dd in unix
my script will generate text file which have two fields
one is date and another is name of the server for example this is sample date which I have to sort based on older to newer date the problem is when I found out sort will... (4 Replies)
I have a file which has 100k+ records like this
abc,05-JUN-1974,def,lkj,aaa
def,11-SEP-1975,ghj,dis,dea
I want to convert ex 05-JUN-1974 to 06/05/1974
Please help me with awk script to convert the whole file into MM-DD-YYYY
Thank you! (2 Replies)
Hi all
I have some pipe-separated data in the form:
5/12/2008 00:00:00|31/1/2009 00:00:00|SOMESTUFF|OTHERSTUFF
12/31/2008 00:00:00|15/1/2009 00:00:00|MORESTUFF|REMAININGSTUFF
1/1/1023 00:00:00|16/5/2047 00:00:00|THEREST|YETMORE
I need to zero-pad the single-digit days and months, using... (3 Replies)
My csv has data like this
x,x,3452,2/18/1986,abc
x,g,19711,1/24/1986,abc
i want to replace date in the following format YYYY-mm-dd
how do i convert using awk script ? (8 Replies)
(Attention: Green PHP newbie !)
I have an online inquiry form, delivering a date in the form yyyy/mm/dd to my feedback form. If the content passes several checks, the form sends an e-mail to me. All works fine. I just would like to receive the date in the form dd/mm/yyyy. I tried with some code,... (6 Replies)
Hello,
I am writing a script that parses different logs and produces one. In the source files, the date is in DD MM YYYY HH24:MI:SS format. In the output, it should be in DD MON YYY HH24:MI:SS (ie 25 Jan 2010 16:10:10)
To extract the dates, I am using shell substrings, i.e.:
read line
... (4 Replies)
Hi I have a problem with Date format in my code.
1st I am trying to convert today's date to yesterday's using
YESTERDAY3=`perl -e '@y=localtime(time()-86400); printf "%04d/%02d/%02d",$y+1900,$y+1,$y;$y;'`
And once it is done I am trying to using the yesterday date in a grep command to... (3 Replies)
I've seen a lot of posts on this and have tried the following:
echo 1257000000| perl -e '($d,$m,$y)=(localtime(time-86400));$m+=1;$y+=1900;printf "$y/$m/$d\n";'
But I am unable to convert a past Epoch date into a format such as YYYY/MM/DD or MM/DD/YYYY.
I am using bash and don't know... (4 Replies)
I am getting output of YYYY-MM-DD and want to change this to DD/MM/YYYY.
When am running the query in 'Todd' to_date(column_name,'DD/MM/YYYY') am getting the required o/p of DD/MM/YYYY, But when am executing the same query(Netezza) in linux server(bash) am getting the output of YYYY-MM-DD
file... (3 Replies)
Discussion started by: Roozo
3 Replies
LEARN ABOUT DEBIAN
sa2
SA2(8) Linux User's Manual SA2(8)NAME
sa2 - Write a daily report in the /var/log/sysstat directory.
SYNOPSIS
/usr/lib/sysstat/sa2
DESCRIPTION
The sa2 command is a shell procedure variant of the sar command which writes a daily report in the /var/log/sysstat/sardd file, where the
dd parameter indicates the current day. The sa2 command handles all of the flags and parameters of the sar command.
The sa2 command is designed to be started automatically by the cron command.
EXAMPLES
To run the sa2 command daily, place the following entry in your root or adm crontab file:
5 19 * * 1-5 /usr/lib/sysstat/sa2 -A &
This will generate a daily report called /var/log/sysstat/sardd It will also remove reports more than one week old.
Debian note
The Debian sysstat package has already placed such an entry in your system crontab. Please refer to the /usr/share/doc/sys-
stat/README.Debian file for details.
FILES
/var/log/sysstat/sardd
Indicate the daily report file, where the dd parameter is a number representing the day of the month.
AUTHOR
Sebastien Godard (sysstat <at> orange.fr)
SEE ALSO sar(1), sadc(8), sa1(8), sadf(1)
http://pagesperso-orange.fr/sebastien.godard/
Linux AUGUST 2010 SA2(8)